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Alex_Xolod [135]
2 years ago
13

PLEASE HELP!!!

Mathematics
1 answer:
AlekseyPX2 years ago
3 0

Answer:

D.

Step-by-step explanation:

Find the average rate of change of each given function over the interval [-2, 2]]:

✔️ Average rate of change of m(x) over [-2, 2]:

Average rate of change = \frac{m(b) - m(a)}{b - a}

Where,

a = -2, m(a) = -12

b = 2, m(b) = 4

Plug in the values into the equation

Average rate of change = \frac{4 - (-12)}{2 - (-2)}

= \frac{16}{4}

Average rate of change = 4

✔️ Average rate of change of n(x) over [-2, 2]:

Average rate of change = \frac{n(b) - n(a)}{b - a}

Where,

a = -2, n(a) = -6

b = 2, n(b) = 6

Plug in the values into the equation

Average rate of change = \frac{6 - (-6)}{2 - (-2)}

= \frac{12}{4}

Average rate of change = 3

✔️ Average rate of change of q(x) over [-2, 2]:

Average rate of change = \frac{q(b) - q(a)}{b - a}

Where,

a = -2, q(a) = -4

b = 2, q(b) = -12

Plug in the values into the equation

Average rate of change = \frac{-12 - (-4)}{2 - (-2)}

= \frac{-8}{4}

Average rate of change = -2

✔️ Average rate of change of p(x) over [-2, 2]:

Average rate of change = \frac{p(b) - p(a)}{b - a}

Where,

a = -2, p(a) = 12

b = 2, p(b) = -4

Plug in the values into the equation

Average rate of change = \frac{-4 - 12}{2 - (-2)}

= \frac{-16}{4}

Average rate of change = -4

The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]

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xenn [34]

Answer:

$2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

Step-by-step explanation:

Let a, b, and c be the fractions of the $12,000 that is invested in the savings, bond, & money fund respectively.

Let S1, S2, S3 be the total monies from the savings, bond, & money fund after the year with interest respectively.

We know that a+b+c=1

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S1+S2+S3 = 12000 + 860

S1+S2+S3 = 12860

From, the question, we know that b = 2a, and c = 1 - 3a based on the condition of 2 times more in the bond account that the savings account.

Thus;

S1 = a(12000)(1.04) = 12480a

S2 = 2a(12000)(1.06) = 25,440a

S3 = (1 - 3a)(12000)(1.09) = 13080 - 39240a

We already know that;

S1+S2+S3 = 12860

Thus, Adding the 3 equations gives;

12480a + 25,440a + 13080 - 39240a = 12860

Thus, simplifying gives;

13080 - 12860 = 39240a - 12480a - 25,440a

220 = 1320a

a = 220/1320

a = 0.1667

So,b = 2 x 0.1667 = 0.3334

c = 1 - (3 x 0.1667)

c = 1 - 0.5

c = 0.5

Thus,

S1 = 12480a = 12480 x 0.1667 ≈ $2080

S2 = 25,440a = 25440 x 0.1667 ≈ $4241

S3 = 13080 - 39240(0.1667) ≈ 6539

So, $2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

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2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a
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Let h = height of the box,
x = side length of the base.

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