Question

Which statement about 6x^2+7x-10 is true

Answer 1

Answer:

A) One of the factor is (x + 2)

Step-by-step explanation:

The given expression is $6x^2 + 7x -10$

Let's factor the given trinomial.

Here we use AC method.

We multiply the value of A and C, then find the factors of AC such that when you add those two factors, we have to get the value B.

Now compare this expression with the general form $AX^2 + Bx + C$ and identify the value of A, B and C.

A = 6, B = 7 and C = -10

Now multiply A and C

AC = 6*-10 = -60

Now we have to find the factors of -60 such that when you add those two factors we have to get 7

12* -5 = -60

13 + (-5) = 7

So the correct factors are -5 and 12

Now use these factors and rewrite the given expression.

$6x^2 + 7x - 10 = 6x^2 +12x - 5x - 10$

Now group the terms and factor it.

$6x(x + 2) -5(x + 2)$

Here (x +2) is common factor, take it out and write the remaining terms in the parenthesis.

(x + 2) (6x - 5)

There are two factors (x +2) and (6x - 5)

One of the factor is (x + 2)

Answer 2

Answer:

One of the factors is (x+2)

Step-by-step explanation:

6x^2+7x-10= (6x-5)(x+2)

=(6x^2-5x)(12x-10)

=x(6x-5)+2(6x-5)

=(6x-5)(x+2)