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hammer [34]
4 years ago
15

Not 100% on how to solve this

Mathematics
1 answer:
noname [10]4 years ago
8 0
44°
137°
223°

are the answer

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Crickets and math <br> Thanks for help
Galina-37 [17]

Answer:

the answer is A

Step-by-step explanation:

4 0
3 years ago
A cyclist rides her bike at a rate of 10 meters per second. What is this rate in kilometers per hour? How many kilometers will t
Monica [59]
10 meters per second converts to 36 kilometers per hour. Therefore to find how far the cyclist goes in 3 hours, you multiply that number by 3 to get 108 kilometers.
6 0
3 years ago
solve 5x^2-7x+2=0 completing the square. what is the constant added on to form the perfect square trinomial
kenny6666 [7]
Best to factor 5 out of the first 2 terms:

5x^2-7x+2=0  =>  <span>5(x^2 - [7/5]x)                          +2=0

Take half of [-7/5]:  That'd be -7/10.

Square 7/10, add it to  </span>5(x^2 - [7/5]x)                          +2=0  and then subtract it:


5(x^2 - [7/5]x)+ 49/100       -  49/100       )                  +2=0

Then we have   5(x- [7/10] )^2 - 49/100 ) + 200/100 = 0

                          5(x-7/5)^2  - 245/100 + 200/100 = 0
                           5(x-7/5)^2 - 45/100 = 0
Dividing all terms by 5,  x-7/5 = plus or minus sqrt( 9/100 )
                                       x-7/5 = plus or minus 3/10

Then one root is x = 7/5 + 3/10, or  x= 17/10  (answer #1)

The other is        x = 7/5 - 3/10, or x = 14/10 - 3/10, or x = 7/10  (answer #2) 
3 0
3 years ago
If 4/5 x blank=2/5 what is blank
Gnoma [55]
<span>4/5 x 1/2 = 2/5

blank = 1/2</span>
6 0
4 years ago
Read 2 more answers
Factorize<br>please <br>help<br>me <br><br><img src="https://tex.z-dn.net/?f=a%20%7B%7D%5E%7B2%7D%20%20-%204b%20%7B%7D%5E%7B4%7D
Vsevolod [243]

Answer:

(a+2b^{2} )(a-2b^2)

Step-by-step explanation:

You have what is called "perfect squares" so you can use the "difference of squares formula to factor:

a^2-b^2=(a+b)(a-b)

So,

a^2-(2b^2)^2

you can work the equation backward now and you will get your original equation.

8 0
3 years ago
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