Least common denominator between 5/6 and 5/9

Does anyone know the answer to this question. I already tried A and C.

Archy [21]

I think the answer would have to be D. If the diameter, which is the distance from one point on the circle through the center to another point on the circle, is halved then the amount of concrete that will be needed will be multiplied by 4. I think that's right I am so sorry in advance if that was incorrect. Have a beautiful rest of your day. Stay safe. C O V I D - 1 9 IS REAL THIS COULD MEAN YOUR LIFE!!!

3 0

3 years ago

Help me PLEASEEEE<br> find the the angles

wel

You need to find x so that then you can do it and you didn’t share a answer so how are we supposed to know??

3 0

3 years ago

PLEASE SHOW YOUR WORK.

schepotkina [342]

Answer:

a) Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7

b) The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as

98 square feet

Step-by-step explanation:

The area in, square feet, of Shawn’s garden is found be calculating 15(2x + 7). Shawn incorrectly says the area can also be found using the expression 30x + 7.

The correct area =

15(2x + 7).

= 30x + 105 square feet

The error in Shawn’s expression is

= 15(2x + 7)

= 30x + 7 square feet

Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7

The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as

30x + 105 square feet - 30x + 7 square feet

= 30x + 105 - (30x + 7)

= 30x - 30x + 105 - 7

= 98 square feet

7 0

3 years ago

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

3 years ago

Ayuda plis es para hoy

aivan3 [116]

Es la segunda media es 1.65, mediana es 1.65, y modo es 1.61

5 0

3 years ago