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balu736 [363]
3 years ago
12

63x^18/9x^2 simplified

Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

7x^16. Step-by-step solution in the attachment.

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Geri believed the answer to one of her homework problems was 2 cubed. After checking her work, she realized the correct answer w
Murrr4er [49]

Answer:

D

Step-by-step explanation:

7 0
2 years ago
A pedestal for a statue is made with 405 cubic feet of concrete.
Pavlova-9 [17]

Answer:

45 square feet

Step-by-step explanation:

we know that

The volume of the pedestal (rectangular prism) is given by the formula

V=Bh

where

B is the area of the rectangular base of pedestal

we have

V=405\ ft^3\\h=9\ ft

substitute the given values in the formula and solve for B

405=B(9)

B=405/9\\B=45\ ft^2

5 0
3 years ago
Read 2 more answers
Pedro is building a playground in the shape of a right triangle. The base of the triangle is 18 yards. The height of the triangl
Bezzdna [24]

Answer:

567 square yards

Step-by-step explanation:

The Area for 1 Triangular playground = 1/2 × Base × Height

The base of the triangle is 18 yards. The height of the triangle is 21 yards.

Hence:

= 1/2 × 18 yards × 21 yards

= 189 square yards

The area of the Triangular 3 playground is given as:

= 3 × 189 square yards

= 567 square yards

6 0
3 years ago
Marcus observed that 8 of the 20 games that he had bowled last week were over 180. What percent of his games were over 180?
shepuryov [24]

Answer:

40%

Step-by-step explanation:

Ok so my brain is sorta not working but it said "hey! 20 divided by 2 is 10!"

So I was like ight and divided 80 by 2 to to get 40%.

Hope this helps.

6 0
2 years ago
What is a number that when you divide it by 2 and subtract 3.8 from the quotient, you get 7?
Black_prince [1.1K]

Let the number x.

Then the number divided by 2 gives

\frac{x}{2}

Subtract 3.8 from the quotient gives

\frac{x}{2}-3.8

Hence,

\frac{x}{2}-3.8=7\begin{gathered} \frac{x}{2}-3.8=7 \\ \frac{x}{2}=7+3.8=10.8 \\ \Rightarrow x=2\times10.8=21.6 \end{gathered}

x = 21.6

5 0
1 year ago
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