Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Hello!
The original equation is:
200 = (5w ÷ 2)8
This problem can be written as:
200 = (5w/2)8
And you can then reduce the numbers with 2:
200 = 5x * 4
200 = 20x
10 = x
Your correct answer is 10.
So it would be in six years because if you do it, it would be
garden 1: 2,4,6,8
garden 2: 3,6,9
and the lowest common multiple is 6 so in 6 years is when it will happen again
If 1 inch is 13.5 feet, then 5 inches = (13.5 * 5) = 67.5 ft