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3 years ago

How to rearrange 3x+6y-1=0

1 answer:

6 0

3x+6y-1=0
All the letters and all the numbers should be on seperate sides so...
The -1 is added onto the zero like this:
3x+6y=0+1
3x+6y=1

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Could someone answer and explain these please? Thank you!

Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

$x=(10 \times t)+(1 \times u)$

$x=10t+u$

The two digit number 'y' is obtained by reversing the digits of x.

So, $y=(10 \times u)+(1 \times t)$

$y=10u+t$

Now, the value of x-y is expressed as:

$x-y=(10t+u)-(10u+t)$

$x-y=10t+u-10u-t$

$x-y=9t-9u$

$x-y=9(t-u)$

So, $9(t-u)$ is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = $\frac{a}{1-r}$

Since, the sum of the given infinite geometric series = 200

Therefore, $\frac{a}{1-r}=200$

Since, r=0.15 (given)

$\frac{a}{1-0.15}=200$

$\frac{a}{0.85}=200$

$a=0.85 \times 200$

a=170

The nth term of geometric series is given by $ar^{n-1}$ .

So, second term of the series = $ar^{2-1}$ = ar

Second term = $170 \times 0.15$

= 25.5

So, the second term of the geometric series is 25.5

Step-by-step explanation:

8 0

3 years ago

????????? Help pls & thanks

mina [271]

Top left is the right answer hope this helps <3

7 0

2 years ago

Lewis fills his thermos with 2 liter of water. Garret fill his thermos with 1 of water. How many more milliliter of water does l

cluponka [151]

For this case we have to:

Lewis carries 2 liters of water

Garret carries 1 liter of water

So, Lewis has 1 liter of water more than Garret.

By definition we have that 1 liter equals 1000 milliliters.

Thus, Lewis carries 1000 milliliters more water than Garret.

Answer:

1000 milliliters

7 0

3 years ago

A truck loaded with 8000 electronic circuit boards has just pulled into a firm’s receiving dock. The supplier claims that no mor

Juliette [100K]

Answer:

The 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

Let X = number of boards that fall outside the most rigid level of industry performance specifications.

In a random sample of 300 boards the number of defective boards was 12.

Compute the sample proportion of defective boards as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

3 0

3 years ago

Challenge You have 2 different savings accounts. For Account A, the simple interest earned after months is $. For Account B,

Debora [2.8K]

Answer and Step-by-step explanation:

The computation is shown below;

As we know that

The simple interest is

Simple interest = Principal × rate × time

For Account A, the principal would be

2 = Principal × 3.2% × 3

So, the principal is $20.83

For account B, the principal would be

38.50 = Principal × 2.2% × 30

So, the principal is $58.33

Now the interest for both the accounts are as follows

For account 1

= $20.83 × 3.2%

= $0.67

And, for the account 2

= $58.33 × 2.2%

= $1.28

As it can be seen that the account 2 has the highest interest

The same is to be considered

7 0

2 years ago