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fomenos
3 years ago
6

Evaluate 17s^2 + 32s +180

Mathematics
1 answer:
dezoksy [38]3 years ago
7 0
Answer: 66s + 180

How:

17 s ^ { 1 } 2 + 32 s + 180
Calculate s to the power of 1 and get s.

17s\times 2+32s+180
Multiply 17 and 2 to get 34.

34s+32s+180
Combine 34s and 32s to get 66s.

Final answer should be 66s + 180
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First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.

Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.

So x+4 divides 2x^3+2x^2-19x+20. 
<span>(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).
 
If we factor out a two, we can use the quadratic formula.

2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0
 
then x=-4, (3+i)/2, or (3-i)/2
</span>we have two imaginary number.
I hope it helped you
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3 years ago
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