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4 years ago

Write an equation for the following: The difference of six and a number is equal to 36.

Mathematics

1 answer:

mylen [45]4 years ago

6 0

Answer:

6-x=36

x=-30.........

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4 years ago

If f(x) = x2 + 2x + 3, what is the average rate of change of f(x) over the interval [-4, 6]?

a_sh-v [17]

Calculating the value of f(x) for the given interval.

For x = - 4, f(x) = f(- 4) = (- 4)^2 + 2 (- 4) + 3 = 11

For x = 6, f(x) = f(6) = (6)^2 + 2 (6) + 3 = 51

Now using formula for the calculation of average rate of change of f(x) over the given interval of [- 4, 6];

(f(b) – f(a)) / b – a = (f(6) – f(- 4)) / 6 – (- 4) = (51 -11) / 10 = 4

So option “E” is correct.

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3 years ago

Multiply. Write your answer in scientific notation. (3 * 1010)(2 x 1010)

strojnjashka [21]

Answer:

6,120,600

Step-by-step explanation:

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3 years ago

What is the side length of the eectagkes

dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

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4 years ago