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4 years ago

Which linear equations have one solution? Check all that apply.

Mathematics

2 answers:

STALIN [3.7K]4 years ago

7 0

Answer:

Step-by-step explanation:

olve: x - 6 = -12 Solve: x + 6 = -12 Solve: x/6 = -12 Solve: 6x = -12 ... Solve: 3 + 2x = 4x - 1 Solve: 3x + 4(x -1) = 2 Solve: 4x + 2 - 3x + 5 - 2(x + 5) = (2x - 5) + (3x + 4) ... Notice in equation 10, that until you get to the equation "-x - 3 = 5x - 1, " all ... 3 = 2x - 1 +1 = + 1 4 = 2x 4/2 = 2x/2 2 = x, the answer, 9.) Solve: 3 + 2x = 4x - 1

horrorfan [7]4 years ago

5 0

Answer:

A,C,D

Step-by-step explanation:

Use thing on your shoulder called a brain.

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I need help with this please

AnnZ [28]

Hi there! The answer is C.

The area of the square in the middle is the following:
$length \: \times \: width \: = 5 \times 5 = 25$
Hence, the area of the square is 25 cm^2.

The area of one triangle is the following:
$0.5 \times base \: \times \: height \: = 0.5 \times 5 \times 8 = 20$
Hence, the total area of the four triangles is 4 × 20 = 80 cm^2.

Therefore, the total area of the pyramid is 80 + 25 = 105 cm^2. The answer is C.

6 0

4 years ago

Read 2 more answers

3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili

choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

8 0

3 years ago

Find the area of the circle to the nearest whole number, if necessary!

astra-53 [7]

Answer:

The circle has an area of about 1385 square mm.

Step-by-step explanation:

Let's recall that circles have an area that can be found with the following formula:

$A=\pi r^{2}$

where r is the radius of the circle.

Now, focus your eyes on the circle. We are shown that the diameter of this circle is 42 mm, but we only want the radius. Since the radius is half the diameter, the radius is 21 mm. Now, we can solve for the area of the circle.

$A=\pi (21)^2\\A=441\pi \\A=1385.44236...$

So, to the nearest whole number, the area of the circle is 1385 square mm.

5 0

2 years ago

What is the area of the shaded region?

kolezko [41]

Answer:

110 cm^2

Step-by-step explanation:

The first thing that you need to do is find the area of triangle AFE. The area of a triangle is always base*height/2. So in this case, that would be 10*6 divided by 2, which is 30 cm. Next, you will need to know the area of triangle ECB. Using that same formula, you will get 8*10/2, which is 40 cm. Finally, you will need to find the area of the whole rectangle. The area of a rectangle is always the length times the width. In this case, you would have 10*18, which is 180 cm. To get your final answer, you need to subtract the areas of the unshaded area from the whole area. That would be 180-(30+40), which is 110 cm. I hope this helped!

6 0

3 years ago

I need help with this one can someone show me step by step

Gelneren [198K]

Answer:

Step-by-step explanation:

You are given one angle and one side are similar

for Angle-Side-Angle you obviously need one more angle attached to the given side

A angle r = ~ angle c

5 0

2 years ago