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3 years ago

What is 98.044 rounded to the nearest hundred

1 answer:

4 0

98.044 rounded to the nearest hundredth is:

98.04 because 4 is less than 5

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Can anyone help me on this? I need an exact answer please no guesses

Maksim231197 [3]

x = 32°

The triangle has 2 equal sides and is therefore isosceles, thus the 2 base angles are also congruent.

The 2 base angles are of size x°

x = $\frac{180 - 116}{2}$ = $\frac{64}{2}$ = 32

6 0

3 years ago

Read 2 more answers

3(-4x - 3) + 50 - 5= 0

UNO [17]

Answer:

-12x-9+50-5=0

-12x+41-5=0

-12x+36=0

-12x=0-36

x= -36/-12

x = 3 Answer...

hope it helps

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3 years ago

2. Bohol:

mel-nik [20]

Answer:

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3 years ago

What is f^7 . f^1 please help

telo118 [61]

Answer:

is f^8

Step-by-step explanation:

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3 years ago

For some constants a and b let \[f(x) = \left\{ \begin{array}{cl} 9 - 2x & \text{if } x \le 3, \\ ax + b & \text{if } x

Viktor [21]

Answer:

The value of a+b is 4.

Step-by-step explanation:

The given function is

$f(x) = \left\{ \begin{array}{cl} 9 - 2x & \text{if } x \le 3, \\ ax + b & \text{if } x > 3. \end{array} \right.$

It is given that for some constants a and b the function f has the property that f(f(x))=x for all x.

For x≤3,

$f(x)=9-2x$

For x>3,

$f(x)=ax+b$

At x=0,

$f(0)=9-2(0)=9$

$f(f(0))=f(9)\Rightarrow a(9)+b=9a+b$

Using property f(f(x))=x,

$f(f(0))=0$

$9a+b=0$ .... (1)

At x=1,

$f(1)=9-2(1)=7$

$f(f(1))=f(7)\Rightarrow a(7)+b=7a+b$

Using property f(f(x))=x,

$f(f(1))=1$

$7a+b=1$ .... (2)

Subtract equation (2) from equation (1).

$9a+b-(7a+b)=0-1$

$2a=-1$

Divide both sides by 2.

$a=-\frac{1}{2}$

Substitute this value in equation (1).

$9(-\frac{1}{2})+b=0$

$b=\frac{9}{2}$

The value of a is $-\frac{1}{2}$ and value of b is $\frac{9}{2}$ . The value of a+b is

$a+b=-\frac{1}{2}+\frac{9}{2}$

$a+b=4$

Therefore the value of a+b is 4.

5 0

3 years ago