All categories

3 years ago

What is the most likely reason that England is warmer than Labrador?

1 answer:

8 0

It was thought that Western Europe is kept warmer than it's latitude would suggest because of the Gulf Stream, which shoots warm equatorial waters up along the eastern coast of North America and across the North Atlantic to Europe

You might be interested in

What is a semicolon used for? Question 9 options:

andrew11 [14]

Joining together two COMPLETE phrases.

When joining together two sentences with a conjunction, you would use a comma.

It wouldn't be used to describe a list or show that someone is stuttering.

I hope this helps!
~cupcake

5 0

4 years ago

Read 2 more answers

The main purpose of the passage is to

tatuchka [14]

Answer:

What passage...?

Explanation:

5 0

3 years ago

Help please!!! :(((((((((((

diamong [38]

I'm not good at math but im going to take a wild guess and say its 280 degrees

8 0

4 years ago

Read 2 more answers

17.2 defining and evaluating the basic trigonometric functions answer key

Brut [27]

An example of basic trigonometric functions question is find tan $\frac{11\pi }{4}$ .

<h3>What are trigonometric functions?</h3>

The term trigonometric function is known to be made up of functions such as sine (sin), cosine (cos), tangent (tan), etc., that stands for the ratios of sides of all right triangles.

To solve for tan $\frac{11\pi }{4}$

It will be $\frac{11\pi }{4}$ = 2 $\pi$ + $\frac{3\pi }{4}$

θ = $\pi -\frac{3}{4} \pi$

θ = $\frac{\pi }{4}$

To know the right angle,

θ = $\frac{\pi }{4}$ x 180/4 = 45⁰

tan θ = 1

Therefore, tan $\frac{11\pi }{4}$ = -1

Learn more about trigonometric functions from

brainly.com/question/24349828

5 0

2 years ago

At a large corporation, the distribution of years of employment for the employees has mean 20.6 years and standard deviation 5.3

Cerrena [4.2K]

Answer:

Yes

Explanation:

The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma}\\\\where\ \mu=mean.\sigma=standard\ deviation, x=raw\ score.\\\\For\ a \ sample\ size\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }$

For a normal distribution with a mean of μ and standard deviation σ, For any sample size (n) drawn from this population, the sample mean is normally distributed, with mean $\mu_x=\mu$ and standard deviation $\sigma_x=\frac{\sigma}{\sqrt{n } } \\\\$ .

Hence given that a mean of μ = 20.6 years and standard deviation σ = 5.3 years, for a sample size of 100:

mean $\mu_x=\mu=20.6\ years$ and standard deviation $\sigma_x=\frac{\sigma}{\sqrt{n } } =\frac{5.3}{\sqrt{100} }=0.53\ years \\\\$ .

7 0

3 years ago