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mash [69]
2 years ago
7

Black Ops 3 For Ps4 Players Here

Computers and Technology
1 answer:
masha68 [24]2 years ago
6 0

Answer:

Love black ops

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What is included on the HP PC Hardware Diagnostics 3-in-1 USB Key that allows you to recover systems that cannot boot?
algol13

Answer:

HP PC Hardware Diagnostics UEFI

Explanation:

The 3-in-1 HP PC Hardware Diagnostics UEFI USB Key helps the client distinguish potential software, hardware, and Operating System issues. Both older and newer HP Desktop and Laptop PCs come with this tool installed. By default, it operates outside the OS to detach equipment issues from other system issues. In the event you do not have it pre-installed, you can get it from the official HP site.

3 0
3 years ago
Mobile devices have their own OSs, tailored to their handheld needs, which means they are not immune to what?
NikAS [45]

Answer:

Malware

Explanation:

Malware is used in many types of software included handheld OS's

6 0
2 years ago
The LList class is (mostly) the same one discussed in lecture, but you must write a sort() function that uses one of the three i
Vladimir79 [104]

Answer:

see explaination

Explanation:

#include <iostream>

#include <string>

using namespace std;

class LinkedList{

class Node{

public :

int data;

Node* next;

Node(int data){

this->data = data;

next = NULL;

}

};

public :

Node *head;

LinkedList(){

this->head = NULL;

}

void insert(int d){

Node* new_node = new Node(d);

new_node->next = head;

head = new_node;

}

// sort the list with selection sort algorithm.

// Pick the smallest element in the unsorted array and place in the first element in the unsorted.

void sort_list(){

if (head == NULL){

return;

}

Node* current = head;

while (current->next != NULL){

Node* min_node = current;

Node* traverse = current->next;

while(traverse != NULL){

if(traverse->data < min_node->data){

min_node = traverse;

}

traverse = traverse->next;

}

int temp = current->data;

current->data = min_node->data;

min_node->data = temp;

current = current->next;

}

}

void print_list(){

Node* current = head;

while(current !=NULL){

cout<<current->data<<" ";

current = current->next;

}

cout<<"\n";

}

};

int main(){

LinkedList ll;

for(int i=0;i<10;i++){

ll.insert(i);

}

ll.print_list();

cout<<"*******************************************\n";

ll.sort_list();

ll.print_list();

cout<<"*******************************************\n";

}

8 0
3 years ago
G The method of mapping where each memory locationis mapped to exactly one location in the cache is
Otrada [13]

Answer:

Direct Mapped Cache

Explanation:

Given that a Direct Mapped Cache is a form of mapping whereby each main memory address is mapped into precisely one cache block.

It is considered cheaper compared to the associative method of cache mapping, and it is faster when searching through it. This is because it utilizes a tag field only.

Hence, The method of mapping where each memory location is mapped to exactly one location in the cache is "Direct Mapped Cache"

4 0
2 years ago
This graph shows both a reflection and a
Tpy6a [65]

Answer:

y=-3x-×-1 I think it's answer is it

6 0
3 years ago
Read 2 more answers
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