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LUCKY_DIMON [66]
4 years ago
9

Choices: A) 7 B) 12 C) 9 D) 6Please help!!

Mathematics
2 answers:
PilotLPTM [1.2K]4 years ago
7 0

the answer is C:9

This is how i did it

CR

CV

CP

FR

FV

FP

BP

BR

BV

these are all the possible combinations



bonufazy [111]4 years ago
3 0

There are 9 possible combinations, because you can have 3 main dishes, and each of thise have 3 side dishes that can go with them. I hope this helps! Could I possibly get brainliest.

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Suppose an investment of $3,800 doubles in value every decade. the function gives the value of the investment after x decades. h
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D. $7,600 3,800 x 2= 7,600
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3 years ago
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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
Afina-wow [57]

Answer:

13.86 ft/sec

Step-by-step explanation:

If we let x = distance batter has run at time t and  D = distance from second base to the batter at  time t, then we know \frac{dx}{dt}=31 ft/s and we want \frac{dD}{dt} when he is halfway (at x = 45).

Using Pythagoras theorem

D^2=90^2+(90-x)^2\\\text{Differentiating with respect to t}\\2D\frac{dD}{dt}=0+2(90-x)(-1)\frac{dx}{dt}\\2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}

When x=45

D^2=90^2+(90-x)^2\\D^2=90^2+(90-45)^2\\D^2=10125\\D=\sqrt{10125}

2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}\\2\sqrt{10125}\frac{dD}{dt}=-2(90-45)(31)\\\frac{dD}{dt}=\frac{-2(45)(31)}{2\sqrt{10125}} =-13.86ft/s

Thus, when the batter is halfway to first base, the distance between second base and the batter is  decreasing at the rate of about 13.86 ft/sec.

4 0
4 years ago
Solving a Quadratic Equation
Dafna1 [17]

Answer:

The factored form of the equation is (x + 4)(x – 6) = 0.

Step-by-step explanation:

(x – 4)(x + 2) = 16

Foil the left side

x^2 +2x-4x-8 =16

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x^2 -2x-8 = 16

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Factor the left hand side

What two numbers multiply to -24 and add to -2

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(x-6) (x+4) =0

Solving using the zero product property

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7 0
3 years ago
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What is the equation of the line that passes through (0, -2) and has a slope of O?
Dmitriy789 [7]

Answer:

The equation of the line that passes through (0, -2) and has a slope of 0 is \mathbf{y=-2}

Step-by-step explanation:

We need to find the equation of the line that passes through (0, -2) and has a slope of 0?

The equation of line can be expressed in slope-intercept form y=mx+b where

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We are given slope = 0 so, m = 0

Now, y-intercept can be found using slope m=0 and point (0,-2)

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Now, the equation of the line having slope m=0 and y-intercept b=-2 is:

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So, the equation of the line that passes through (0, -2) and has a slope of 0 is \mathbf{y=-2}

5 0
3 years ago
915 how do you write it in words
Bas_tet [7]
Nine hundred and fifteen
8 0
4 years ago
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