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Finger [1]
3 years ago
11

PLEASE HELP! I WILL MARK AS BRAINLIEST!! I REALLY NEED SOMEONES HELP!

Mathematics
1 answer:
Andrej [43]3 years ago
4 0

Since this is subtraction, everything must be turned negative in the second polynomial.

(6x^2 - 5x) - (2x^2 + 3x - 2)

6x^2 - 5x - 2x^2 - 3x - (-2)

6x^2 - 5x - 2x^2 - 3x + 2

Now, reorder the terms to make it easier.

6x^2 - 2x^2 - 5x - 3x + 2

Now, just combine like terms.

4x^2 - 5x - 3x + 2

4x^2 - 8x + 2

There’s the answer!

Please consider marking this answer as Brainliest to help me advance.

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Y = x – 10<br><br> 2x + y = 4
Nezavi [6.7K]
I hope this helps you



2x+x-10=4



3x=14



x=14/3



y=14/3-10



y=14-30/3



y=-16/3
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dexar [7]
A/6   -   8

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6 0
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5 0
3 years ago
What is the product of 2xyz -3yz +4xz
mixas84 [53]
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Z(2xy-3y+4x)

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3 0
3 years ago
Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviati
Irina-Kira [14]

The mean absolute deviation for the number of hours students practiced the violin is 6.4.

<h3>What is the mean absolute deviation?</h3>

The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.

Given

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.

The given data set is;

45, 38, 52, 58, 42

Mean Deviation = Σ|x − μ|/N.

μ = mean, and N = total number of values

|x − μ| = |45 − 47| = 2

|38− 47| = 9

|52− 47| = 5

|58− 47| = 11

|42− 47| = 5

The mean absolute deviation for the number of hours students practiced the violin is;

\rm Mean =\dfrac{2+9+5+11+5}{5}\\\\Mean=\dfrac{32}{5}\\\\Mean = 6.4

Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.

To know more about mean value click the link given below.

brainly.com/question/5003198

8 0
2 years ago
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