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Norma-Jean [14]
3 years ago
6

Please help asap 50 pts

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0
If you factor the expression by grouping you should get (3g - 5) (2g +7)

Steps:
1. Factor 11 out of 11g
6g^2 + 11 (g) - 35

2. Rewrite 11 as -10 plus 21
6g^2 + (-10 + 21) g - 35

3. Apply the distributive property
6g^2 + (-10g + 21g) - 35

4. Remove parentheses
6g^2 - 10g + 21g - 35

5. Group the first two and the last two terms
(6g^2 - 10g) + (21g - 35)

6. Factor out the greatest common factor from each group
2g (3g - 5) + 7 (3g - 5)

7. Factor out the greatest common factor, 3g - 5
(3g - 5) (2g + 7)


Therefore the answer is A
Allushta [10]3 years ago
7 0
6g^2+11g-35=6g^2+21g-10g-35=3g(2g+7)-5(2g+7)=(2g+7)(3g-5)
Answer: A. (3g - 5)(2g + 7)

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The value of   \dfrac{ 2}{3} log(6400) - \dfrac{1}{3} log(1600)  in terms of s will be

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I had the same question on my test the other day hope this helped.

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