All categories

3 years ago

Find the range and interquartile range for the data represented by the box plot.

Mathematics

2 answers:

Roman55 [17]3 years ago

6 0

Lowest value: 15

Highest value: 30

Median: 23

Lower quartile: 18

Upper quartile: 27

Range: highest value - lowest value =

Range: 30 - 15 = 15

(IQR) Interquartile range: Upper quartile - Lower quartile =

(IQR): 27 - 18 = 9

Anarel [89]3 years ago

3 0

Given:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

Range:

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

Interquartile range:

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

You might be interested in

A girl ran from her home to a store at the rate of 6 mph, and she walked back home at the rate of 4 mph. if it took 15 minutes f

viva [34]

Home is 0.6 miles away from the store

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:-

Total time taken by girl to complete the trip = 15 minutes = $\frac{1}{4}$ hours

Speed while riding going = 6 miles per hour

Speed while coming back = 4 miles per hour

Total time taken by girl =

Time taken while going + Time taken while coming back - (1)

Let x be distance from home to store

$\frac{x}{6}$ = Time taken while going

$\frac{x}{4}$ = Time taken while coming back

Substituting in (1) we get

$\frac{1}{4} = \frac{x}{6} + \frac{x}{4}$

$\frac{1}{4} = \frac{2x + 3x}{12}$

$\frac{1}{4} = \frac{5x}{12}$

$x= \frac{12}{20}$

x = 0.6 miles

Thus home is 0.6 miles away from the store

Learn more about time related here :

brainly.com/question/12759408

#SPJ4

6 0

1 year ago

Please help ASAP I am in desperate need

Vlad1618 [11]

Answer:

x = 9

TH = 12

Step-by-step explanation:

since TM is half of HM, the equation is:

2(21 - x) = 3x - 3

42 - 2x = 3x - 3

45 = 5x

x = 9

TH = 21 - x

TH = 21 - 9

TH = 12

8 0

3 years ago

3+(-7) solve for x help meee

garik1379 [7]

Answer:

3 + ( -7 )

7 - 3

= 4 is the answer

6 0

3 years ago

Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interv

sleet_krkn [62]

Answer:

(0, 16]

Step-by-step explanation:

∑ₙ₌₁°° (-1)ⁿ⁺¹ (x−8)ⁿ / (n 8ⁿ)

According to the ratio test, if we define L such that:

L = lim(n→∞) |aₙ₊₁ / aₙ|

then the series will converge if L < 1.

aₙ = (-1)ⁿ⁺¹ (x−8)ⁿ / (n 8ⁿ)

aₙ₊₁ = (-1)ⁿ⁺² (x−8)ⁿ⁺¹ / ((n+1) 8ⁿ⁺¹)

Plugging into the ratio test:

L = lim(n→∞) | (-1)ⁿ⁺² (x−8)ⁿ⁺¹ / ((n+1) 8ⁿ⁺¹) × n 8ⁿ / ((-1)ⁿ⁺¹ (x−8)ⁿ) |

L = lim(n→∞) | -n (x−8) / (8 (n+1)) |

L = (|x−8| / 8) lim(n→∞) | n / (n+1) |

L = |x−8| / 8

For the series to converge:

L < 1

|x−8| / 8 < 1

|x−8| < 8

-8 < x−8 < 8

0 < x < 16

Now we check the endpoints. If x = 0:

∑ₙ₌₁°° (-1)ⁿ⁺¹ (0−8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° -(-1)ⁿ (-8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° -(8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° -1 / n

This is a harmonic series, and diverges.

If x = 16:

∑ₙ₌₁°° (-1)ⁿ⁺¹ (16−8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° (-1)ⁿ⁺¹ (8)ⁿ / (n 8ⁿ)

∑ₙ₌₁°° (-1)ⁿ⁺¹ / n

This is an alternating series, and converges.

Therefore, the interval of convergence is:

0 < x ≤ 16

Or, in interval notation, (0, 16].

4 0

3 years ago

Wake up to reality! Nothing ever goes as planned in this world. The longer you live, the more you realize that in this reality o

Kamila [148]

Exactly, Thank you again for these quotes!

-p.s you are loved <3

EDIT: THANKS FOR THE POINTS >:3

3 0

3 years ago