All categories

3 years ago

Find the range and interquartile range for the data represented by the box plot.

Mathematics

2 answers:

Roman55 [17]3 years ago

6 0

Lowest value: 15

Highest value: 30

Median: 23

Lower quartile: 18

Upper quartile: 27

Range: highest value - lowest value =

Range: 30 - 15 = 15

(IQR) Interquartile range: Upper quartile - Lower quartile =

(IQR): 27 - 18 = 9

Anarel [89]3 years ago

3 0

Given:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

Range:

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

Interquartile range:

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

You might be interested in

Please help... Solve using the quadratic formula x^2 - 6x - 40=0

Tasya [4]

The answer is

X=10 or X= -4

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B15%7D" id="TexFormula1" title="\frac{6}{15}" alt="\frac{6}{15}" align="absmid

aleksklad [387]

So what you do,is you add them together to get 13/10 but then you can also simplify it but you can keep the answer to 13/10

3 0

2 years ago

Read 2 more answers

3x+2y=25 5x+6y=57 What the x and y? HELP

son4ous [18]

Answer:

x=4.5

y=5.75

Step-by-step explanation:

since you dont have much time to wait, i wont put an explanation here

6 0

3 years ago

Read 2 more answers

Find the domain and the range of the following function

adell [148]

Answer:

cjvnvhhvhjgufvjffuhghhhvc

6 0

2 years ago

Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).

ale4655 [162]

Answer:

The required equation is:

$y = -\frac{3}{2}x+9$

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

$(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)$

We will find the slope of given line segment first

$m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}$

Let m_1 be the slope of perpendicular bisector then,

$m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}$

Now the mid-point

$(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)$

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

$y = m_1x+b$

Putting the value of slope

$y= -\frac{3}{2}x+b$

Putting the point (2,6) to find the y-intercept

$6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9$

The equation is:

$y = -\frac{3}{2}x+9$

7 0

2 years ago