Answer:
Option A is correct that is ( 1 , -3 )
Step-by-step explanation:
Given Equation:
y + 3 = 2(x - 1)
To find: point which lies on line of given equation from given points
A). ( 1 , -3 )
x = 1 , y = -3
LHS = y + 3 = -3 + 3 = 0
RHS = 2(x - 1) = 2(1 - 1) = 0
LHS = RHS
Therefore, This Point lie on the line.
B). ( 0 , 0 )
x = 0 , y = 0
LHS = y + 3 = 0 + 3 = 3
RHS = 2(x - 1) = 2(0 - 1) = -2
LHS ≠ RHS
Therefore, This Point doesn't not lie on the line.
C). ( 2 , 1 )
x = 2 , y = 1
LHS = y + 3 = 1 + 3 = 4
RHS = 2(x - 1) = 2(2 - 1) = 2
LHS ≠ RHS
Therefore, This Point doesn't not lie on the line.
D). ( 2 , 9 )
x = 2 , y = 9
LHS = y + 3 = 9 + 3 = 12
RHS = 2(x - 1) = 2(2 - 1) = 2
LHS ≠ RHS
Therefore, This Point doesn't not lie on the line.
E). ( 1 , -4 )
x = 1 , y = -4
LHS = y + 3 = -4 + 3 = -1
RHS = 2(x - 1) = 2(1 - 1) = 0
LHS ≠ RHS
Therefore, This Point doesn't not lie on the line.
F). ( -1 , -6 )
x = -1 , y = -6
LHS = y + 3 = -6 + 3 = -3
RHS = 2(x - 1) = 2(-1 - 1) = -4
LHS ≠ RHS
Therefore, This Point doesn't not lie on the line.
