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3 years ago

What's the circumference if d=17?

Mathematics

2 answers:

meriva3 years ago

7 0

The circumference would be 53.38 because the formula on finding the circumference is pi times the diameter.

Effectus [21]3 years ago

4 0

The formula for the circumference is 2 pi r. So you multiply 2 times pi times 8.5.

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Please help me on this geometry i’ll mark u the brainliest

kicyunya [14]

Answer:

Step-by-step explanation:

If XY is bisector of angle AXN then: $\dfrac{YN}{AY}=\dfrac{XN}{AX}$

$\dfrac4{12}=\dfrac{XN}{18}\\\\XN=\dfrac4{12}\cdot18\\\\XN=6$

5 0

3 years ago

2.86 = ? tenths + 6 hundredths =

kherson [118]

To get 2.8 from 0.1 you have to multiply by 28. So 28 tenths. Which leaves 0.06 which is 0.01 times 6. So 6 hundredths

5 0

3 years ago

Read 2 more answers

Find the area of the shaded region <br><br> A. 4.421<br> B. 3.982<br> C.4.215<br> D. 3.769

jasenka [17]

Answer:

b i think

Step-by-step explanation:

3 0

3 years ago

The area of the scale model of a playground is 6 square yards. The scale model is enlarged by a scale factor of 3 to create the

REY [17]

Answer:

B: 54 square feet

Step-by-step explanation:

There are 3 feet in 1 yard. The scale model is 6 square yards.

Multiply 6 by 3 to get the amount of square yards.

There are 18 square yards in the actual playground.

Since there are 3 feet in a yard, multiply 18 by 3.

This gives you your answer:

54 square feet

6 0

3 years ago

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A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0

3 years ago