1a) Possible rational roots will be of the form
±{divisor of 10}/{divisor of 4}
Divisors of 10 are {1, 2, 5, 10}
Divisors of 4 are {1, 2, 4}
Then possible rational roots are
{±1/4, ±1/2, ±1, ±5/4, ±2, ±5/2, ±5, ±10}
1b) Your answer is correct.
2) One additional root will be the conjuate of the given complex root.
5 -3i
3) If one root is 5 -√7, another will be 5 +√7. Then your polynomial is
P(x) = (x -(5 -√7))*(x -(5 +√7)) = (x -5)^2 -(√7)^2
P(x) = x^2 -10x +18
I think it would be (x+7)/7
Answer:
Step-by-step explanation:
We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.
Our success is winning the prize, p =40/100 = 0.4
Then failure q = 1-0.4 = 0.6
Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.
P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)
=
+
+
+ 
=
+
+
= ![(0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}](https://tex.z-dn.net/?f=%280.6%29%5E%7Bn%7D%2Bn%280.4%29%280.6%29%5E%7Bn-1%7D%2B%5Btex%5D%5Cfrac%7Bn%28n-1%29%280.4%29%5E%7B2%7D0.6%5E%7Bn-2%7D%7D%7B2%7D%20%2B%5Cfrac%7Bn%28n-1%29%28n-2%290.4%5E%7B3%7D0.6%5E%7Bn-3%7D%7D%7B6%7D)
I can’t help you I’m sorry
E, D, and A.
well because it can be divide my 5.