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SVEN [57.7K]
3 years ago
12

0.8b = 1.12HELP please please

Mathematics
2 answers:
timama [110]3 years ago
5 0
B=1.4
Is the answer. 

This is just for more characters <span />
erma4kov [3.2K]3 years ago
5 0
The answer would be: B = 1.4

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Given the following function, find f(-4), f(0), and f(3).
shutvik [7]
You plug in the given value for x.

F(-4)=(-4)2-4
F(-4)=-8-4
F(-4)=-12

F(0)=(0)2-4
F(0)=0-4
F(0)=-4

F(3)=(3)2-4
F(3)=6-4
F(3)=2
8 0
3 years ago
Read 2 more answers
Please help help help help help help​
nevsk [136]

Answer:

y is equal to (-1/4)x

hope this helped! :)

7 0
3 years ago
PLEASE HELP!!!! What statement describes the limitation for the reasonable domain compared to the mathematical domain?
Afina-wow [57]
Question 4 of 5 Page 4 Question 4 (1 point) f(x) - 0.5x + 3 The function is used to estimate the number of pounds of potatoes a caterer plans to make depending on the number of people being served, X. The mathematical domain for the function is the set of real numbers. Which statement describes the limitation for the reasonable domain compared to the mathematical domain? O O O a b C d The reasonable domain contains only real numbers greater than 3. The reasonable domain contains only positive whole numbers The reasonable domain contains only rational numbers greater than 3. the reasonable domain contains only negative whole numbers Next Page Back were to search
3 0
3 years ago
Solve x2 + 8x + 22 = 0 by completing the square.
Liula [17]

Answer:

A)

Step-by-step explanation:

the solution of a squared equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case

a = 1

b = 8

c = 22

x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =

= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =

= -4 ± sqrt(-6) = -4 ± i×sqrt(6)

6 0
3 years ago
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
3 years ago
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