Answer:
A. 
Step-by-step explanation:
Hi there!
We are given right triangle PQR, with PR=5, RQ=12, and PQ=13
We want to find the value of sin(Q)
Let's first recall that sine is 
In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse
So that means that sin(Q) would be 
Substituting the values of PR and PQ gives sin(Q) as , which is A
Hope this helps!
+ 32
and
- 5
will do that job for you.
Answer:
6x -16
Step-by-step explanation:
f(x) = 6x + 2
f(x-3) =
Replace x with x-3
f(x) = 6(x-3) + 2
Distribute
= 6x - 18 +2
= 6x -16
A =bh
Plug in values and solve for height (h).
A=3.36
b=2.8
3.36 = 2.8h
/2.8 /2.8
1.2 = h
Base and Height doubled:
b = 2.8
h = 1.2
2(2.8)=5.6
2(1.2)=2.4
Plug in new b and h to area equation given to find area:
5.6(2.4) = 13.44
Resulting parallelogram area = 13.44 ft^2
3*4*4=48
she can make 48 different sandwiches
