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ryzh [129]
3 years ago
7

A potential benefit of telecommuting is that it _____.

Business
2 answers:
den301095 [7]3 years ago
5 0

the answer is: a. reduces employee turnover

in business, potential benefit refers to the benefit that might or might not occurs depending on the performance that created from a certain decision.

Telecommunication is useful for the employers to communicate with the employees even if they not in close proximity. This allow employees to work at home and have more balance between their personal life and professional life. This balance would increase their comfort level in working with the employer and reduce the employee turnover.

IrinaK [193]3 years ago
5 0

Correct Answer is A, Reduces employee turnover.

First of all we need to know the concepts of Employee turnover and Telecommuting. After knowing about them, we will be able to better relate them.

Employee Turnover is the number of employees leaving an organization or the number of employees being replaced by the organization. 4

Telecommuting is the process of doing work from home through internet.

Now people work from home, they are highly motivated towards their work because they take out time and work for the organization from home. This reduces the risk of employees leaving the organization. Because themselves are committed to work, they are not forced to work, rather they work with their will. So in this way, telecommuting reduces the risk of employee turnover.

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Kerekes Manufacturing Corporation has prepared the following overhead budget for next month.
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Answer:

Detailed solution is given below in attached diagram:

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Despite its drastic downsizing a decade ago under a federally funded bailout and bankruptcy​ restructuring, General Motors again
zalisa [80]

Answer:

The question is actually missing (see attached image):

the answer is:

D. Less than that of its competitors.

Explanation:

Personally, I believe that GM is an extremely spoiled child that refuses to assume responsibility for its continuous and never ending mistakes. GM has either filed for bankruptcy or threatened to do so twice in the last 30 years or so, and every time the US government has to bail them out. But GM keeps doing things wrong.

It doesn't matter if you like their cars or not, GM is terribly managed. No other company in US history has received so much financial aid from the government and continued to lose money and work inefficiently. The problem is that whenever things go wrong, stockholders lose their money but the executives keep getting tens of millions of dollars. If a company is managed in such a disastrous way, their top management shouldn't get paid that much.

A car factory costs a lot of money, and not using it efficiently is outrageous considering GM's history. If they had never received a cent from the government, then its only their problem. But the government lost $11.2 billion on GM's last bailout. During the 1980s GM lobbied fro the government to impose import quotas on Japanese cars because they were better cars and GM couldn't compete against them. So whenever they do things wrong, big brother has to help them. During the last couple of years GM had to sell most of its foreign operations in order to get cash, and you generally do not make money by selling your assets.

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3 years ago
A cylindrical part of diameter d is loaded by an axial force p. this causes a stress of pya, where a 5 pd2y4. if the load is kno
raketka [301]

Here is the correct question.

A cylindrical part of diameter d is loaded by an axial force p. this causes a stress of P/A, where A= πd²/4. if the load is known with an uncertainty of ±10 percent, the diameter is known within ±5 percent (tolerances), and the stress that causes failure (strength) is known within ±15 percent, determine the minimum design factor that will guarantee that the part will not fail.

Answer:

the minimum design factor that will guarantee that the part will not fail. = 1.434

Explanation:

Looking at the uncertainty; loss of strength must be raised to \dfrac{1}{0.85} due to the stress that causes the failure (strength)  is known within ±15% uncertainty.

Looking at the uncertainty; the maximum allowable load  must be reduced to \dfrac{1}{1.1} because the load is known with an uncertainty of ±10.

Looking at the uncertainty; the diameter must be raised to \dfrac{1}{0.95}  because the diameter is known within an uncertainty of ±5.

The decrease in the maximum allowable stress can be estimated as:

\sigma' = \dfrac{P'}{A'}

where,

\sigma = stress

P = load

A = cross-sectional area of the cylinder

∴

\sigma' = \dfrac{P'}{\dfrac{\pi}{4}(d')^2}

replacing P' with \dfrac{1}{1.1}P   and d' with \dfrac{1}{0.95}d, we have:

\sigma' = \dfrac{(\dfrac{1}{1.1})\times p }{\dfrac{\pi}{4}(\dfrac{1}{0.95 } d)^2 }

\sigma' =\dfrac{P}{\dfrac{\pi}{4}d^2} (\dfrac{\dfrac{1}{1.1} }{(\dfrac{1}{0.95})^2 }) }

\sigma' =\sigma \times (\dfrac{\dfrac{1}{1.1} }{(\dfrac{1}{0.95})^2 }) }

\sigma' =\sigma \times 0.82045

\dfrac{\sigma' }{\sigma } =0.82045

Thus, the uncertainty in diameter and the load of the allowable stress needs to decrease to 0.82045

Now, the minimum design factor that will ascertain that the part will not fail can be computed as:

n_d = \dfrac{loss  \ of  \ function \  parameter }{maximum \  allowable \ parameter}

where;

the design factor = n_d

n_d =\dfrac{\dfrac{1}{0.85} }{0.82045}

the design factor  n_d = 1.434.

Thus,  the minimum design factor that will guarantee that the part will not fail. = 1.434

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In phenomenological studies, researchers strive to ensure that their own preconceived beliefs and opinions do not influence the
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Answer:

D is the correct answer.

Explanation:

It is an important part of some qualitative research philosophies especially for those in which interviews and observations need to be taken. It is also known as mind mapping or Phenomenological reduction. The purpose of this technique is to develop a non-judgmental research team, whose preconceived notions won't affect the perception of the phenomenon. This must be done with care.

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