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Bess [88]
3 years ago
4

What is the midpoint of the segment shown below

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

I'm pretty sure it's B

Katen [24]3 years ago
6 0

(5/2,-7/2)

midpoint=(x1+X2/2),(y1+y2/2)

=((4+1)/2),((-1+-6)/2)

=(5/2),(-7/2)

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On the grid below, which point is located in the quadrant where the x-coordinate is a positive number and the y-coordinate is a
Ann [662]

Answer:

d

Step-by-step explanation:

d=(x, y) =(8,-4) so 4th quadrant

8 0
3 years ago
What is the value of w?
DedPeter [7]
The side opposite the 30o angle is 1/2 W. That is just a property of a 30 - 60 - 90 triangle. Use that fact to set up the pythagorean relationship.

w^2 = (1/2 w)^2 + (7 * sqrt(3)) ^2
w^2 = 1/4 w^2 + 49*3
w^2 = 1/4 w^2 + 147
3/4 w^2 = 147
w^2 = 147 * 4/3
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4 0
4 years ago
Solve. 4x – 2(–2x – 3) = 10x A. –8 B. 3 C. no solution D. all real numbers
irinina [24]
The answer is b x= 3

5 0
3 years ago
The price of a 5-minute phone call is $1.75. What is the price of a 12-minute phone call?
Ksju [112]

Answer:

$4.20

Step-by-step explanation:

you first do 1.75 divided by 5 which gives you .35

so you do .35 times 12 which gives you 4.2

6 0
3 years ago
A circular region has a population of about 15,500 people and a population density of about 775 people per square kilometer. Fin
Reil [10]

Answer:

2.5 km

Step-by-step explanation:

First, find the area of the region:

  • A circular region has a population of about 15,500 people;
  • A population density of about 775 people per square kilometer.

So, there are 15,500 :775=20 square kilometers.

Now, let x kilometers be the radius of the circular region, then

A_{\text{circilar region}}=\pi r^2\\ \\20=\pi r^2\\ \\r^2=\dfrac{20}{\pi}\approx 6.366198\\ \\r=\sqrt{3.366198}\approx 2.523

To the nearest tenth this is 2.5 km.

6 0
3 years ago
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