subsitute x = 6 into the lengths
3(6) -7
18 - 7
11cm
(6) + 5
11cm
therefore it is a square when x = 6 because the sides are all equal
9x^2 - 8x - 1 = 0
(9x + 1(x - 1) = 0
x = -1/9 , 1
x intercepts are -1/9 and 1.
So attached is a picture of the triangle you are talking about and listed under are the choices:
A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
<span>D.) Tan Z=a/b
</span>
The answer would then be
B. SinX = c/b.
Just remember SOH CAH TOA:
Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent
Using the triangle in the scenario, you just need to identify which side is which.
Given m∠ZAdjacent = b
Opposite = a
Hypotenuse = c
SinZ= a CosZ = b TanZ= a
c c b
Given m∠X:
Adjacent = b
Opposite = a
Hypotenuse = c
SinX= <u> b </u> CosX =<span><u> a </u></span> TanX=<span><u> b </u></span>
c c a
So the answer is B.
Attached is a picture of how I assigned the sides depending on the angle used.