Hello :
the solution :x²-6x+9=0 is the x- intresept and graph of f(x) =x²-6x+9
the solution is : x=3
the solution :x²-6x+9=0 is the x- intresept and graph of f(x) =x²-6x+9
the solution is : x=3
OAB is a sector of a circle of radius 12 cm Angle AOB= 60º Work out the length of the arc B. Give your answer in terms of pie.
1 answer:
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Answer:
x ∈ [-2, 7]
Step-by-step explanation:
The given equation ...
x^2 -5x -4 ≤ 10
can be rewritten as ...
x^2 -5x -14 ≤ 0
and factored as ...
(x +2)(x -7) ≤ 0
Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.
x ∈ [-2, 7]
Answer:
option-C
Step-by-step explanation:
We are given row-echelon form
So, we can write equation from matrix as
Let's assume
now, we can find x and y
so, we get solutions as
where t can be any real numbers