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charle [14.2K]
3 years ago
5

ANSWER THESE QUESTIONS FOR 20 POINTS!

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0
1. B
2. D
Hope this helps:3
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Yes compund interest is always greater than simple interest 

simple interest = principal

compound interest = principal + accumulated interest
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2 years ago
What is the solution to the equation 400 - 8m =216
777dan777 [17]

Answer: m=23

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
2 years ago
Complete the square for the following expression
Marysya12 [62]

Answer:

16, x+4^2

Step-by-step explanation:

To find the perfect square with an A factor of 1, just double the next number.

4 0
2 years ago
The function g(t)=−16t2+vt+h represents the height of an object, g, in feet, above the ground in relation to the time, t, in sec
kow [346]

Answer:

A) g(t) = - 16*t² + 80*t

B) domain is  ( 0 ≤ t ≤ 5 )

Step-by-step explanation:

A) for the model rocket

h = 0    and  v = 80 feet/sec

Then the equation     g(t)  = -16*t² + v*t + h

became

g(t) = - 16*t² + 80*t + 0         g(t) = - 16*t² + 80*t

B) The equation  g(t) = - 16*t² + 80*t  is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t)  then the biggest value for t = 5 from

-16*t²  +  80*t  ≥ 0

-16*t  ≥ -80       16*t ≤ 80

t ≤ 5

And the domain is  ( 0 ≤ t ≤ 5 )

8 0
2 years ago
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