Answer:
AB = 16 Units
Step-by-step explanation:
In the given figure, CD is the diameter and AB is the chord of the circle.
Since, diameter of the circle bisects the chord at right angle.
Therefore, AE = 1/2 AB
Or AB = 2AE...(1)
Let the center of the circle be given by O. Join OA.
OA = OD = 10 (Radii of same circle)
Triangle OAE is right triangle.
Now, by Pythagoras theorem:
![OA^2 = AE^2 + OE^2 \\10^2 = AE^2 + 6^2 \\100= AE^2 + 36\\100-36 = AE^2 \\64= AE^2 \\AE = \sqrt{64}\\AE = 8 \\\because AB = 2AE..[From \: equation\: (1)] \\\therefore AB = 2\times 8\\\huge \purple {\boxed {AB = 16 \: Units}}](https://tex.z-dn.net/?f=%20OA%5E2%20%3D%20AE%5E2%20%2B%20OE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E10%5E2%20%3D%20AE%5E2%20%2B%206%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E100%3D%20%20AE%5E2%20%2B%2036%5C%5C%3C%2Fp%3E%3Cp%3E100-36%20%3D%20AE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3E64%3D%20AE%5E2%20%5C%5C%3C%2Fp%3E%3Cp%3EAE%20%3D%20%5Csqrt%7B64%7D%5C%5C%3C%2Fp%3E%3Cp%3EAE%20%3D%208%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Cbecause%20AB%20%3D%202AE..%5BFrom%20%5C%3A%20equation%5C%3A%20%281%29%5D%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Ctherefore%20AB%20%3D%202%5Ctimes%208%5C%5C%3C%2Fp%3E%3Cp%3E%5Chuge%20%5Cpurple%20%7B%5Cboxed%20%7BAB%20%3D%2016%20%5C%3A%20Units%7D%7D%20)
Answer:
3. 91.125
4. 30.375
Step-by-step explanation:
just multiply all of the sides
MARK ME BRAINLIEST
Answer:
x=-3, x=1, x=8
Step-by-step explanation:
When you have to find the zero of an equation like (x+3) all you have to do is solve for x.
x+3=0 equal the equation to zero
x+3-3=0-3 cancel out 3
x=-3 answer
If you have to find the zero of an equation like f(x)=-2x^2 - 5x + 7 then you would have to factor the equation.
7*-2=-14 multiply
-7 & 2 find the two numbers that when multiplied =14 and when added = -5
(2x^2 + 2) (-7x + 7) replace -5 with -7 & 2
-2x (x - 1) -7 (x - 1) factor
(x - 1) (-2x - 7) rewrite
1st: x - 1 = 0
x = 1 : Answer
2nd: -2x - 7= 0
-2x - 7 + 7 = 0 + 7
-2x = 7
-2x / -2 = 7 / -2
x = 7 / -2 : Answer
Idek lol but yeah have a good day
It looks like a reflection over the y-axis. There's a formula you can use when doing reflections over the y-axis, (x,y) is going to become (-x, y) thats also the coordinate rule I think.
If you apply that rule to each point you should get the reflected image.
G- (1, 3) then (-x,y) to get (-1,3)
E- (1, 2) then (-x,y) to get (-1, 2)
V- (5, 1) then (-x,y) to get (-5, 1)
X- (3, 3) then (-x,y) to get (-3, 3)