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Sauron [17]
4 years ago
8

How do i solve this problem?

Mathematics
1 answer:
uranmaximum [27]4 years ago
4 0

Answer:

Step-by-step explanation:

Simplifying

N(t) = 300.9   Multiply N * t  tN = 300.9  Solving  tN = 300.9   Solving for variable 't'.   Move all terms containing t to the left, all other terms to the right.   Divide each side by 'N'.  t = 300.9N-1   Simplifying  t = 300.9N-1

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3x-1=4x+8-x<br><br> Find X Value
Marrrta [24]

Answer:

is the question correct, you end up with no X's

3x -4x + x = 9

or I've got it wrong

6 0
2 years ago
Read 2 more answers
There are 75 students in a speech contest. Yesterday, 2/5 of them gave their speeches. Today, 1/3
Trava [24]
<h3>Answer: 30</h3>

Work Shown:

2/5 of 75 = (2/5)*75 = 0.4*75 = 30

Yesterday 30 people gave speeches. There are 75-30 = 45 people left.

1/3 of 45 = (1/3)*45 = 15

Then another 15 people gave speeches today. So there are 45-15 = 30 people who haven't given their speeches yet.

4 0
3 years ago
Given the formula, solve for the indicated variable. <br> F=9/5c + 32 for c
SVEN [57.7K]
F = \frac{9}{5}c + 32   Subtract 32 from both sides
F - 32 = \frac{9}{5}c   Mutliply both sides by <span>\frac{5}{9} to cancel out the fraction
</span>\frac{5}{9}F - 17 \frac{7}{9} = c   Switch the sides to make it easier to read
c = \frac{5}{9}F - 17 <span>\frac{7}{9} </span>
3 0
3 years ago
29/6<br> Write as a mixed number
Sever21 [200]

Answer:

4 5/6

Step-by-step explanation:

This would be the answer as a mixed number

4 0
3 years ago
Read 2 more answers
Katie has a collection of nickels, dimes and quarters with a total value of
garik1379 [7]

10d+ 25q+5n= 805

D= n+8

Q= n+ 5



10d+ 25q+5n= 805

10(n+8)+25(n+5)+5n=805

10n+80+25n+125+5n=805

40n+205=805

40n=805-205

40n= 600

N=600/40

N= 15


D= n+8

D= 15+8

D= 23


Q=n+5

Q=15+5

Q=20


So 15 nickels ,23 dimes and 20quarters .


To check

15(0.05)= $0.75

23(0.10)=$2.30

20(0.25)=$5.00


Add it

5.00+2.30+0.75=8.05

7.30+.75=8.05

8.05=8.05

5 0
3 years ago
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