Question

What is the point-slope form of a line with slope 4/5 that contains the point

Answer 1

The point-slope form of the line is:

y - 1 = (4/5)*(x + 2)

How to get the linear equation?

The point-slope form of a line is:

y - y₁ = m*(x - x₁)

Where m is the slope and (x₁, y₁) is a point on the line.

Here we know that m = 4/5, and the line contains the point (-2, 1).

Then we can write the line in the point-slope form as:

y - 1 = (4/5)*(x - (-2))

y - 1 = (4/5)*(x + 2)

If you want to learn more about linear equations:

brainly.com/question/1884491

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