Answer:0.75 milligrams will be present in 24 hours
Step-by-step explanation:
Step 1
The formula for radioactive decay can be written as
N(t)=No (1/2)^(t/t 1/2)
where
No= The amount of the radioactive substance at time=0=milligrams
t 1/2= the half-life= 6 hours
t=24 hours
N(t) = the amount at time t
Step 2--- Solving
N(t)=No (1/2)^(t/t 1/2)
=N(t)=12 x ( 1/2) ^ (24/6)
= 12 x (1/2) ^4
= 12 x 0.0625
= 0.75 milligrams
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa
D hope this helps :) good luck
Answer:
C)17
Step-by-step explanation:
5+y+8
let y=4
5+4+8
9+8
17
