Answer:
Step-by-step explanation:
solve each inequality:
A : x+6<8 , x<-8-6 , x<-14
B: x+4≥-6 , x≥-10
C: x-3>-10 , x>-7
D:x≤-9
since -12 is on the left side of the number line then x≤ -9 would be the solution
Answer:
B. x= 4
Step-by-step explanation:
We know that,
The result for the intersection of the secant and the tangent is given by by the figure below,
![UV^{2}=UX\times UY](https://tex.z-dn.net/?f=UV%5E%7B2%7D%3DUX%5Ctimes%20UY)
According to the question, we have,
![8^{2}=x(12+x)](https://tex.z-dn.net/?f=8%5E%7B2%7D%3Dx%2812%2Bx%29)
i.e. ![64=12x+x^2](https://tex.z-dn.net/?f=64%3D12x%2Bx%5E2)
i.e. ![x^2+12x-64=0](https://tex.z-dn.net/?f=x%5E2%2B12x-64%3D0)
Now, the solution of a quadratic equation
is given by, ![x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%7B2a%7D)
So, we get,
implies a= 1, b= 12 and c= -64.
Thus, the solution is given by,
![x=\frac{-12\pm \sqrt{12^{2}-4\times 1\times (-64)}}{2\times 1}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-12%5Cpm%20%5Csqrt%7B12%5E%7B2%7D-4%5Ctimes%201%5Ctimes%20%28-64%29%7D%7D%7B2%5Ctimes%201%7D)
i.e. ![x=\frac{-12\pm \sqrt{144+256}}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-12%5Cpm%20%5Csqrt%7B144%2B256%7D%7D%7B2%7D)
i.e. ![x=\frac{-12\pm \sqrt{400}}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-12%5Cpm%20%5Csqrt%7B400%7D%7D%7B2%7D)
i.e. ![x=\frac{-12\pm 20}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-12%5Cpm%2020%7D%7B2%7D)
i.e.
and i.e. ![x=\frac{-12+20}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-12%2B20%7D%7B2%7D)
i.e.
and i.e. ![x=\frac{8}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8%7D%7B2%7D)
i.e x= -16 and x= 4.
Since, length cannot be negative.
So, we have, x= 4.
Answer:
(3, -1)
Step-by-step explanation:
Choose a point under the equation.
*It depends what place value needs to be rounded down, but without any specific place values, here are my answers*
<em>600.1</em>
<em>601</em>
<em>600.44</em>
<em>602.1</em>
<em>644.4</em>
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-Hope this helps :)
Answer:
I think that the volume of sphere is the first one