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Ray Of Light [21]
3 years ago
6

Which express can be used to find the surface area of the following square pyramid.

Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer:I believe the answer is the last one d

Step-by-step explanation:

Have I got my answer to this is that I figured out how many fours were on our side was there for four so that equals 16 and then I figured out how many threes or worse that there is for threes which would equal to two sixes and then to six ended up with an equal up to 12 and such as the fours I did 4+4 is eight and then 8+8 is 1216 so the simplest form you can put in it is 16+12 and that’s how they got my answer

Harman [31]3 years ago
3 0

Answer: B: 16+6+6+6+6

Step-by-step explanation:

The area of the base is 16, the area of one triangle on the side is 6, there are four triangles in this prism so the expression should be 16+6+6+6+6

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Polygon ABCDE ~ Polygon FGHIJ<br> What is the scale factor of polygon ABCDE to polygon FGHIJ?
Nataly [62]

Answer:

A. \frac{1}{3}

Step-by-step explanation:

I'm not sure if this is right

5 0
3 years ago
Solve for the base of a triangle where the height is 16cm and area is 104 cm2. What is the base?
Arturiano [62]

Answer:

13cm

Step-by-step explanation:

104 × 2 = 208

208 ÷ 16 = 13cm

(13 × 16) ÷ 2 = 104cm²

6 0
3 years ago
Read 2 more answers
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Find the 12th term of an AP of the form 7, 12, 17, 22
ikadub [295]
Answer: 62

Step-by-Step Explanation:

First Term (a) = 7
Common Difference (d) = 12 - 7 = 5
Term to Find (n) = 12th

Therefore, finding the 12th Term :-
=> a+(n-1)d
= 7 + (12 - 1)5
= 7 + (11)5
= 7 + 55
=> 62

Hence, 12th Term of this AP is 62
4 0
2 years ago
Read 2 more answers
Solve 2x-y &gt; 1 for y
ra1l [238]
The correct answer is 2x-1
4 0
3 years ago
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