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Ilia_Sergeevich [38]
4 years ago
11

The ratio opposite​/adjacent describes which function?

Mathematics
1 answer:
VMariaS [17]4 years ago
8 0

Answer: o/a is the Tangent

Step-by-step explanation:

Sin = o/h

Cos= a/h

Tan = o/a

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Julie wrote the rate $108 in 6 weeks as a unit rate.find her mistake and correct it
Elenna [48]
Her mistake is that you write rates per one unit of measure. The proper rate would be $18/week
7 0
3 years ago
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What’s the sum of 2/5 and 2/4
Mashcka [7]
Find common denominator

5 x 4 = 20

2 x 4 = 8
2 x 5 = 10

8/20 + 10/20 = 18/20

18/20, or 9/10 simplified, is your answer

Hope this helps
5 0
3 years ago
Help me please I need help
Levart [38]

Answer: $130.68

Step-by-step explanation:

Total value = PRT/100

=1452 ×4.5 ×2 /100

=1452×9 /100

= 13068/100

= 130.68

8 0
3 years ago
What is 16 8ths in simplest form
Romashka-Z-Leto [24]
16/8=2/1=2

so just factor out the ones so for example

4/8=1/2 because 1/2 times 4/4=4/8 and 1/2 times 4/4=1/2 times 1=1/2

so 16/8=
factor
16=2 times 2 times 2 times 2
8= 2 times 2 times 2
16/8=2/1 times 2/2 times 2/2 times 2/2=2/1 times 1 times 1 times 1=2/1=2
8 0
3 years ago
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Limit (sin4x-4sinx)/x^3 when x close to zero
BartSMP [9]

\Large \boxed{\sf \bf \ \ \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}=-10 \ \  }

Step-by-step explanation:

Hello, please consider the following.

Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

sin(x) \sim  \left(x-\dfrac{x^3}{3!}\right)\\\\\text{So, in the neighbourhood of 0}\\\\\begin{aligned}(sin(4x)-4sin(x)) &\sim \left( 4x-\dfrac{(4x)^3}{3!}-4x+\dfrac{4x^3}{3!}\right)\\\\&\sim \left(\dfrac{x^3*4*(1-4^2)}{3*2}\right)\\\\&\sim \left(\dfrac{x^3*2*(-15)}{3}\right)\\\\&\sim \left(x^3*2*(-5)\right)\\\\&\sim \left(x^3*(-10)\right)\\\end{aligned}

Then,

\displaystyle \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}\\\\= \lim_{x\rightarrow0} \ {\dfrac{-10*x^3}{x^3}}\\\\=-10

Thank you

4 0
4 years ago
Read 2 more answers
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