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kipiarov [429]
3 years ago
9

Find the value of x​

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

The larger right triangle with hypotenuse x + 5 and short leg x + 2 is similar to the smaller right triangle with hypotenuse x + 2 and short leg x.

Because of this similarity, we have

(x + 5)/(x + 2) = (x + 2)/x

Solve for x:

x(x + 5) = (x + 2)^2

x^2 + 5x = x^2 + 4x + 4

x = 4

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Bezzdna [24]

Answer:

So it gives you a little picture and tells you what would the question be if you had this graph.

Step-by-step explanation:

The correct answer would be B, find the area because the 4x + 3 is your length and 3x is your length, A = length * width. So the answer is B, find the area.

4 0
3 years ago
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The list shows the number of stories in the 11 tallest buildings
Bogdan [553]

answer: mode:40 med:30

8 0
3 years ago
Work out the value of (1.7 × 10⁴) × (8.5 × 10^-2) give your answer in standard form
kogti [31]

Answer:

Step-by-step explanation:

10^4 = 10000

1.7 × 10^4 = 1.7 × 10000

= 17000

10^-2 = 1/10^2= 1/100

8.5 × 10^-2 = 8.5 × 1/100

= 17/200

Final answer = 17000 × 17 / 200

= 1445

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7 0
3 years ago
The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
Aiden owns a food truck that sells tacos and burritos. He sells each taco for $4.75 and each burrito for $7. Yesterday Aiden mad
nevsk [136]

Number of tacos sold is 65 and number of burritos sold is 40

<h3><u>Solution:</u></h3>

Given that Aiden sells each taco for $4.75 and each burrito for $7

Let the number of tacos sold be "t" and number of burritos sold be "b"

Given that Aiden sold 25 more tacos than burritos

t = b + 25 ---- eqn 1

Also given that yesterday Aiden made a total of $588.75 in revenue

number of tacos sold x cost of each tacos + number of burritos sold x cost of each burritos = 588.75

t \times 4.75 + b \times 7 = 588.75

4.75t + 7b = 588.75  ----- eqn 2

Substitute eqn 1 in eqn 2

4.75(b + 25) + 7b = 588.75

4.75b + 118.75 + 7b = 588.75

11.75b = 470

b = 40

Substitute b = 40 in eqn 1

t = 40 + 25

t = 65

Thus the number of tacos sold is 65 and number of burritos sold is 40

5 0
3 years ago
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