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atroni [7]
2 years ago
10

LA DISTANCIA ENTRE LA TIERRA YLA LUNA ES DE 384 392 KM. LOS AUSTRONAUTAS DE LA APOLO XL SALIERON EL 16 DE JULIO DE 1969 DESDE EL

CENTRO ESPACIAL KENNEDY Y ALCANZARON LA ORBITA LUNAR EL 16 DE JULIO DE 1969.SUPONIENDO QUE CADA DIA RECORRIERON LA MISMA CANTIDAD DE KILOMETROS.¿CUANTOS KILOMETROS RECORRIERON POR DIA.
Mathematics
1 answer:
KengaRu [80]2 years ago
4 0

Complete question :

la distancia entre la tierra y la luna es de 384 392 km. Los astronautas de la Apolo XL salieron el 16 de julio de 1969 desde el Centro Espacial Kennedy y al alcanzaron la orbita el 19 de julio de 1969. Suponiendo que cada dia recorrieron la misma cantidad de kilometros cuantos kilometros recorrieron por dia

Responder:

128130,66 kilometros

Explicación paso a paso:

Dado que:

Distancia entre la tierra y la luna = 384,392 km

Tiempo empleado = (19 de julio - 16 de julio) mismo año = 3 días

Velocidad = distancia / tiempo

El tiempo empleado es (3 * 24) = 72 horas

Por lo tanto,

velocidad = 384,392 / 72

= 5338,7777 kilómetros por hora

Dado que se supone que la distancia recorrida diariamente es la misma m:

El número de kilómetros recorridos por día:

5338,7777 kilómetros por hora * 24

= 128130,66 kilometros

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yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

\sqrt{-3x-2} =x+2

squared both sides

-3x-2=(x+2)^2

-3x-2=x^2+4x+4

x^2+7x+6=0

solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

<u><em>Verify each solution</em></u>

substitute the value of x in the original expression

For x=-6

\sqrt{-3(-6)-2} =-6+2

\sqrt{16} =-4

4=-4 ----> is not true

so

Is an extraneous solution

For x=-1

\sqrt{-3(-1)-2} =-1+2

\sqrt{1} =1

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Is the solution

4 0
3 years ago
PLEASE HELP MATH QUESTION PIC BELOW
Vinil7 [7]

Answer:

∠MNP is your answer

Step-by-step explanation:

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Now look at the second triangle, the same double line side (NM), one curve line angle (∠N), and triple line side (NP)

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3 0
2 years ago
A manufactured product has a length that is normally distributed with a mean of 12 cm. The product will be unusable if the lengt
Sav [38]

Answer:

a) σ  = 0,1612

b) P [ 11,75 < X < 12,35] = 0,92,44   or    92,44 %

Step-by-step explanation:

NOTE: I assume the unusable length s 11,5 and less

a) For a normal distribution, the probability of P = 0,01 corresponds to z(score) =  -3,1 then:

- 3,1 = ( X - μ₀ ) / σ

- 3,1 = (11,5 - 12 )/ σ

-3,1 = - 0,5 / σ

σ  = 0,1612

b) If σ = 0,1612

P [ 11,75 < X < 12,35]

z₁ (score)  = ( 11,75 - 12 ) / 0,1612

z₁  = - 0,25/ 0,1612

z₁  = -1,55

From z table  P [ 11,75 < X] = 0,0606

z₂ (score) = ( 12,35 - 12) / 0,1612

z₂ = 0,35 / 01612

z₂ = 2,17

From z table  P [ X < 12,35] = 0,9850

Finally P [ 11,75 < X < 12,35] = 0,9850 -  0,0606

P [ 11,75 < X < 12,35] = 0,92,44   or    92,44 %

5 0
2 years ago
The sum of the angle measures of a triangle is 180°. Find the value of x. Then find the angle measures of the triangle.
MAXImum [283]

Answer:

  • x = 43
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Step-by-step explanation:

The sum of the angles is ...

  x° + (x +8)° + 2x° = 180°

  4x +8 = 180 . . . . . . . . . . . collect terms, divide by °

  x +2 = 45 . . . . . . . . . . divide by 4

  x = 43 . . . . . . . . . . subtract 2

  x +8 = 51

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The angles are 43°, 51°, 86°.

7 0
2 years ago
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notsponge [240]

Answer:

A=150\ cm^2

Step-by-step explanation:

The Hypotenuse of triangle, H = 25 cm

Base = 15 cm

Height = 20 cm

We need to find the area of the triangle. The area of a right-angled triangle is given by :

A=\dfrac{1}{2}\times b\times h\\\\A=\dfrac{1}{2}\times 15\times 20\\A=150\ cm^2

So, the area of the triangle is equal to 150\ cm^2.

4 0
2 years ago
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