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lisabon 2012 [21]
3 years ago
8

What is the value of x? Enter your answer in the box. x = A triangle with midsegment parallel to the base. the left side is labe

led 40 c m below the midsegment and 5 c m above the midsegment. the right side is labeled 2 x + 10 c m below the midsegment and 3 c m above the midsegment.

Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

Answer: 7


Step-by-step explanation:


Viefleur [7K]3 years ago
6 0

Answer: The value of x is 7 cm.

Step-by-step explanation:

Let ABC is a triangle with mid -segment  DE parallel to the base BC.

the left side is labeled 40 cm below the mid -segment

i.e. BD = 40 cm

the left side is labeled 5 cm above the mid -segment

i.e. AD = 5 cm

Similarly,

The right side is labeled 2 x + 10 cm below the mid -segment

i.e. EC = 2x+10

The right side is labeled 3 cm above the mid -segment

i.e. AE = 3 cm

So, By Basic proportionality theorem,

The ratio of the other two sides is equal.

\frac{AD}{DB}=\frac{AE}{EC}\\\\\frac{5}{40}=\frac{3}{2x+10}\\\\\frac{1}{8}=\frac{3}{2x+10}\\\\2x+10=24\\\\2x=24-10\\\\2x=14\\\\x=\frac{14}{2}\\\\x=7 cm

Hence, the value of x is 7 cm.

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I sold 210 subscriptions. The total is 6150 dollars. One year subscription is 23 dollars and a two year subscription is 45 dolla
erica [24]
<h3>150 one year subscription and 60 two year subscription were sold</h3>

<em><u>Solution:</u></em>

Let "a" be the number of one year subscription

Let "b" be the number of two year subscription

Cost of each one year subscription = $ 23

Cost of each two year subscription = $ 45

<em><u>I sold 210 subscriptions</u></em>

Therefore,

a + b = 210

b = 210 - a -------- eqn 1

<em><u>The total is 6150 dollars</u></em>

Therefore,

number of one year subscription x Cost of each one year subscription + number of two year subscription x Cost of each two year subscription = 6150

a \times 23+b \times 45 = 6150

23a + 45b = 6150 -------- eqn 2

<u><em>Substitute eqn 1 in eqn 2</em></u>

23a + 45(210 - a) = 6150

23a + 9450 - 45a = 6150

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<em><u>Substitute a = 150 in eqn 1</u></em>

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3 years ago
A circular fountain 10 feet in diameter has a walk 3 feet wide paved around it. What is the area of the walk?
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The diameter of the centerline of the walkway is 13 ft, so the circumference of that circle is 13π feet. The area of the walk is the product of its centerline length and its width:

A = (13π ft)·(3 ft) = 39π ft² ≈ 122.5 ft²

_____

You can get there also by subtracting the area of the fountain circle from the area of the circle containing walkway and fountain.

... A = (π/4)d² . . . . . . . area for a circle of diameter d

... A = (π/4)((16 ft)² -(10 ft)²) = 39π ft² . . . . . . area difference of interest

3 0
3 years ago
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