Answer:
im in 6th but i gotchu, spilllll
Step-by-step explanation:
Answer:
-143
Step-by-step explanation:
(I THINK)
<h3>150 one year subscription and 60 two year subscription were sold</h3>
<em><u>Solution:</u></em>
Let "a" be the number of one year subscription
Let "b" be the number of two year subscription
Cost of each one year subscription = $ 23
Cost of each two year subscription = $ 45
<em><u>I sold 210 subscriptions</u></em>
Therefore,
a + b = 210
b = 210 - a -------- eqn 1
<em><u>The total is 6150 dollars</u></em>
Therefore,
number of one year subscription x Cost of each one year subscription + number of two year subscription x Cost of each two year subscription = 6150

23a + 45b = 6150 -------- eqn 2
<u><em>Substitute eqn 1 in eqn 2</em></u>
23a + 45(210 - a) = 6150
23a + 9450 - 45a = 6150
22a = 3300
a = 150
<em><u>Substitute a = 150 in eqn 1</u></em>
b = 210 - 150
b = 60
Thus 150 one year subscription and 60 two year subscription were sold
The diameter of the centerline of the walkway is 13 ft, so the circumference of that circle is 13π feet. The area of the walk is the product of its centerline length and its width:
A = (13π ft)·(3 ft) = 39π ft² ≈ 122.5 ft²
_____
You can get there also by subtracting the area of the fountain circle from the area of the circle containing walkway and fountain.
... A = (π/4)d² . . . . . . . area for a circle of diameter d
... A = (π/4)((16 ft)² -(10 ft)²) = 39π ft² . . . . . . area difference of interest