What is the value of x? Enter your answer in the box. x = A triangle with midsegment parallel to the base. the left side is labe
led 40 c m below the midsegment and 5 c m above the midsegment. the right side is labeled 2 x + 10 c m below the midsegment and 3 c m above the midsegment.
2 answers:
Answer: The value of x is 7 cm.
Step-by-step explanation:
Let ABC is a triangle with mid -segment DE parallel to the base BC.
the left side is labeled 40 cm below the mid -segment
i.e. BD = 40 cm
the left side is labeled 5 cm above the mid -segment
i.e. AD = 5 cm
Similarly,
The right side is labeled 2 x + 10 cm below the mid -segment
i.e. EC = 2x+10
The right side is labeled 3 cm above the mid -segment
i.e. AE = 3 cm
So, By Basic proportionality theorem,
The ratio of the other two sides is equal.
Hence, the value of x is 7 cm.
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Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)