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3 years ago

Jill has a photograph that is 4 inches wide by 6 inches high. If she enlarges it so that the width is 12

Mathematics

1 answer:

Nadya [2.5K]3 years ago

5 0

Answer:

The inches in height will be 18 inches.

Step-by-step explanation:

Okay so we know that the original width is 4 inches and she enlarged that to 12 inches

So what we first have to do is find out how much did the photograph "grow" per se. To find this we have to divide 12 by 4. 12 divided by 4 = 3.

So, the width of the photograph grew "times 3" inches

Now whatever you do to the width you have to do to the height. In this case, what is "3 times" 6 (which is the height). 3 times 6 = 18 inches

So in simpler words 12 divided 4 = 3 x 6 = 18 inches

The inches in height will be 18 inches.

Jill has a square with a width of 12 inches, and a height of 18 inches.

Have a wonderful day!

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3 years ago

6,528 divided by 8 and also 6,349 divided by 9

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2 years ago

Plz help me thanks very nuch whoever helped me

photoshop1234 [79]

Answer:

(1) 56 miles/hour

Step-by-step explanation:

We need to find the average rate of change from t = 2 to t = 9.

At t = 2 hours, d = 106 miles.

At t = 9 hours, d = 498 miles.

The average rate of change in function f(x) from x = a to x = b is

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3 years ago

Josiah, the manager of a pet store, bought 72 oz of water conditioner to use in his fish tanks. His small tanks would require 2

kodGreya [7K]

If we are going to analyze the problem very well, the equation that we will be able to make would be: 2x + 6y = 72

72 is the oz of water conditioner to use in his fish tanks.

small tanks would require 2 oz of conditioner

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There is only one point which satisfy's the above equation.That is the points of (0, 12) and (36, 0)

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3 years ago

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

$(\left {{20} \atop {2}} \right. )$ $=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

$(\left {{3} \atop {2}} \right. )$ $=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$\frac{3}{190}\\ =0.01579\\=0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

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2 years ago