WILL MARK BRAINLIEST TO WHOMEVER IS RIGHT!!!!!!

Keith as 11/12 hours to play, he has already played 1/4. which is the best estimate of the fractional part of an hour he has lef

____ [38]

Answer:

The best estimate is greater than 1/2 but less than 3/4

Step-by-step explanation:

If you multiply 1/4 by 3/3 (which is also 1), you can change the denominator without changing the value. So 1/4 is equal to 3/12.

Since keith has 11/12 hours to play, and he has already played 3/12 hours, subtract 3/12 from 11/12 to get 8/12 hours. This is how much time he has left to play.

If you simplify 8/12 hours, you get 2/3 hours.

So the best estimate would be: greater than 1/2 but less than 3/4.

4 0

2 years ago

Help me with this problem !!!!!!!!!!

Mamont248 [21]

Answer:

Hi, your answer is y= $-\frac{1}{2} x$ -3

Step-by-step explanation:

We will use the slope-intercept formula which is

$\frac{y2-y1}{x2-x1}$

We will use two points in this case I'll use

(-2,-2) and (-8,1)

$\frac{1-(-2)}{-8-(-2)}$ = $-\frac{3}{6}$ which can be simplified as $-\frac{1}{2}$

Your Y will be -3

which your final answer will be y=-1/2x-3

Hope this helps :)

3 0

3 years ago

2 Antonio is a set designer. He is gluing ribbon on 4 square and 2 triangular posters to be used as stage props in an upcoming p

Lana71 [14]

Answer:

89283

Step-by-step explanation:

8 0

2 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

2 years ago

In which number is the value of the 5 ten times greater than the value of the 5 in 654,321? 658,321 536,401 65,892 58

krok68 [10]

Answer:

536,401

Step-by-step explanation:

the 5 is in the ten thousands column in 654,321. you have to times the number by ten to see what column it would be in, 6,543,210. The 5 is now in the hundred thousands column. The only number there with the 5 in in the hundred thousands column is 536,401.

5 0

2 years ago