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3 years ago

Whats the lowest common multiple of 120 and 19600

Mathematics

2 answers:

Lesechka [4]3 years ago

5 0

Answer: 19600

Step-by-step explanation:

19600/120 = 160

Levart [38]3 years ago

4 0

Answer:

Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

Least common multiple (LCM) of 19600 and 19619 is 384532400.

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make a box-and-whisker plot for the data. numbers of colors in a country's flag :3,2,2,4,4,3,6,3,5,3,4,1

Irina-Kira [14]

Answer: see attachment

<u>Step-by-step explanation:</u>

Put the numbers in order from smallest to biggest:

1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 6

↓ ∨ ↓

Q1 Median Q3

Q1 median = (2+3)/2 = 2.5 <---- left side of box plot

Median = (3+3)/2 = 3 <---- Vertical Line of box plot

Q3 median = (4+4)/2 = 4 <---- right side of box plot

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3 years ago

The sea turtle habitat at the zoo is made by connecting two large aquariums. The first aquarium is 6\text { m}6 m6, space, m lon

iren [92.7K]

First aquarium dimensions:

Length = 6 m.

Width = 4 m and

Height = 2 meter.

Second aquarium dimensions:

Length = 8 m.

Width = 9 m and

Height = 3 meter.

We know formula for volume of a cuboidal box = Length*Width*Height.

Plugging values of length, width and height of first aquarium in formula of volume. We get

V1 = 6*4*2 = 48 m^3.

Plugging values of length, width and height of second aquarium in formula of volume. We get

V2 = 8*9*3 = 216 m^3.

In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.

Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.

Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.

8 0

3 years ago

What is the distance between 5,4 and -1,1

spayn [35]

Answer:

3 $\sqrt{5}$

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)

d = $\sqrt{(-1-5)^2+(1-4)^2}$

= $\sqrt{(-6)^2+(-3)^2}$

= $\sqrt{36+9}$

= $\sqrt{45}$

= 3 $\sqrt{5}$ ← exact value

≈ 6.71 ( to 2 dec. places )

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3 years ago

The difference of the product of 3 and m<br> minus the quotient of m divided by 2<br> m=6

s2008m [1.1K]

Answer:5m/2

Step-by-step explanation:

3m-m/2

(2×3m-1×m)/2

(6m-m)/2=5m/2

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3 years ago

An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh

Rzqust [24]

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<h3>What is a confidence interval of proportions?</h3>

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z is the critical value.

n is the sample size.

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