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AfilCa [17]
3 years ago
15

Whats the lowest common multiple of 120 and 19600​

Mathematics
2 answers:
Lesechka [4]3 years ago
5 0

Answer: 19600

Step-by-step explanation:

19600/120 = 160

Levart [38]3 years ago
4 0

Answer:

Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

Least common multiple (LCM) of 19600 and 19619 is 384532400.

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make a box-and-whisker plot for the data. numbers of colors in a country's flag :3,2,2,4,4,3,6,3,5,3,4,1
Irina-Kira [14]

Answer:  see attachment

<u>Step-by-step explanation:</u>

Put the numbers in order from smallest to biggest:

1, 2, 2, 3, 3, 3,         3, 4, 4, 4, 5, 6

        ↓              ∨                ↓

       Q1        Median          Q3

Q1 median = (2+3)/2 = 2.5  <---- left side of box plot

Median = (3+3)/2 = 3          <---- Vertical Line of box plot

Q3 median = (4+4)/2 = 4    <---- right side of box plot

3 0
3 years ago
The sea turtle habitat at the zoo is made by connecting two large aquariums. The first aquarium is 6\text { m}6 m6, space, m lon
iren [92.7K]

First aquarium dimensions:

Length = 6 m.

Width = 4 m and

Height = 2 meter.

Second aquarium dimensions:

Length = 8 m.

Width = 9 m and

Height = 3 meter.

We know formula for volume of a cuboidal box = Length*Width*Height.

Plugging values of length, width and height of first aquarium in formula of volume. We get

V1 = 6*4*2 = 48 m^3.

Plugging values of length, width and height of second aquarium in formula of volume. We get

V2 = 8*9*3 = 216 m^3.

In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.

Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.

Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.

8 0
3 years ago
What is the distance between 5,4 and -1,1
spayn [35]

Answer:

3\sqrt{5}

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (5, 4) and (x₂, y₂ ) = (- 1, 1)

d = \sqrt{(-1-5)^2+(1-4)^2}

   = \sqrt{(-6)^2+(-3)^2}

   = \sqrt{36+9}

   = \sqrt{45}

   = 3\sqrt{5} ← exact value

   ≈ 6.71 ( to 2 dec. places )

8 0
3 years ago
The difference of the product of 3 and m<br> minus the quotient of m divided by 2<br> m=6
s2008m [1.1K]

Answer:5m/2

Step-by-step explanation:

3m-m/2

(2×3m-1×m)/2

(6m-m)/2=5m/2

5 0
3 years ago
An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh
Rzqust [24]

Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0
2 years ago
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