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Aleks [24]
2 years ago
6

Thanks if you help.....

Mathematics
1 answer:
marissa [1.9K]2 years ago
5 0

Answer:

I'm guessing it's D.

Step-by-step explanation:

Sorry if wrong :> Hope i helped! Have a awesome day!!! You're a great hooman ^_^ Please mark brainliest !!

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I need help please?!!!!
Neporo4naja [7]

Answer:

Yes.

Step-by-step explanation:

7 0
3 years ago
There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?
lisov135 [29]
First, lets figure out how many pencils we will need. so we can do that by 4 pencils x 28 children and we get 112. Then if there are 8 pencils in a package, we divide 112 by 8 and get 14
4 0
3 years ago
Read 2 more answers
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the
Darya [45]

Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

48360     47800        560

38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

8 0
3 years ago
2. Starting at a fixed time, each car entering an intersection is observed to see whether it turns left (L), right (R), or goes
jasenka [17]

Answer:

Natural numbers (integers greater than zero)

X = 3,  5,  4,  4,  3

Step-by-step explanation:

The least number of cars that can be observed in this experiment is 1, if the first car turns left. On the other hand, the experiment could go on forever if no car ever turns left, thus the highest number of cars approaches infinite.

The possible values of X are integers greater than zero, which are known as the Natural numbers.

If X = number of cars observed, simply count the number of letters in each outcome for the value of X:

Outcome = RRL, AARRL, AARL, RRAL, ARL

            X = 3,  5,  4,  4,  3

7 0
3 years ago
S is a subset within a universal set, U
nataly862011 [7]
Keys on a keyboard because it can’t be letters because there are numbers and punctuation marks, it can’t be numbers because there are letters and punctuation marks, it can’t be punctuation merks either cause there are letters and numbers. So the only option left is keys on a keyboard cause it has all letters numbers and punctuation marks
4 0
1 year ago
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