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Virty [35]
3 years ago
14

A test to detect an infection gives a positive result 98% of the time if a person is infected. It is 97% accurate for people who

are not infected. % of results will be false negatives, and % of results will be false positives.
Mathematics
2 answers:
Murljashka [212]3 years ago
7 0

Answer:

2%

3%

Step-by-step explanation:


sergeinik [125]3 years ago
5 0
Consider this:

If a test gives a positive result for an infected person 98% of the time, that means that 2% of the time, it gives a negative result for an infected person, which would be a false negative.

Then,

if the test is 97& accurate (not precise) for non-infected people, that means that it gives a negative result 97& of the time. So a positive result will be given 3% of the time for non-infected people, which is considered a false positive.
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1. Let f(x) = x + 3 and g(x) = 3x + 5. Find f(g(4)) - g(f(4)) 2. Let f(x) = 5x^2 - 5. What is f(f(x))? 3. Let f(g(x)) = 3x + 3 a
ludmilkaskok [199]

Answer:

1. f(g(4)) - g(f(4)) = -6

2. f(f(x)) = 125x^4 - 250x^2 + 120

3. a + b = 0

4. g(4) = -9

Step-by-step explanation:

1.

First we need to find f(4) and g(4):

f(4) = 4 + 3 = 7

g(4) = 3*4 + 5 = 17

Then, we find g(f(4)) = g(7):

g(7) = 3*7 + 5 = 26

And we find f(g(4)) = f(17):

f(17) = 17 + 3 = 20

so f(g(4)) - g(f(4)) = 20 - 26 = -6

2.

To find f(f(x)), we use the value of f(x) for every x in f(x):

f(f(x)) = 5*(f(x))^2 - 5 = 5*(5x^2 - 5)^2 - 5 = 5*(25x^4 - 50x^2 + 25) - 5

f(f(x)) = 125x^4 - 250x^2 + 120

3.

To find f(g(x)), we use the value of g(x) for every x in f(x):

f(g(x)) = g(x) + 6 = ax + b + 6 = 3x + 3

ax + (b+6) = 3x + 3 -> a = 3 and b = -3

a + b = 3 - 3 = 0

4.

If we assume g(x) = ax + b, we have:

g(f(x)) = a*(2x - 3) + b = 2ax - 3a + b = 5 - 4x

2a = -4 -> a = -2

-3a + b = 5

6 + b = 5 -> b = -1

g(x) = -2x - 1

g(4) = -2*4 - 1 = -9

7 0
3 years ago
At the movies, we had 286 people buy tickets. The adult tickets were $12 and the children's tickets were $4. The total sold was
Elina [12.6K]

103 adults and 183 children's attended

<em><u>Solution:</u></em>

Let "a" be the number of adults attended

Let "c" be the number of children attended

Cost of 1 adult ticket = $ 12

Cost of 1 children ticket = $ 4

At the movies, we had 286 people buy tickets

Therefore,

number of adults attended + number of children attended = 286

a + c = 286 ---- eqn 1

The total sold was $1968

Therefore,

number of adults attended x Cost of 1 adult ticket + number of children attended x Cost of 1 children ticket = 1968

a \times 12 + c \times 4 = 1968

12a + 4c = 1968 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

a = 286 - c -- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

12(286 - c) + 4c = 1968

3432 -12c + 4c = 1968

-8c = 1968 - 3432

-8c = -1464

8c = 1464

<h3>c = 183</h3>

<em><u>Substitute c = 183 in eqn 3</u></em>

a = 286 - 183

<h3>a = 103</h3>

Thus 103 adults and 183 children's attended

6 0
4 years ago
Help please its percents ! I need
harina [27]
X %  = x/100 as a fraction
so 0.75 % = 0.75 / 100  = 75/10000 or 0.0075

so 0.75% of 560  = 560 * 0.0075 = 4.2
George was correct.
4 0
3 years ago
Read 2 more answers
Solve n^4-11n^2+30÷n^4-7n^2+10
Morgarella [4.7K]
Factor the numerator and denominator...

(n^4-5n^2-6n^2+30)/(n^4-2n^2-5n^2+10)

[n^2(n^2-5)-6(n^2-5)]/[n^2(n^2-2)-5(n^2-2)]

[(n^2-5)(n^2-6)]/[(n^2-5)(n^2-2)]  notice the (n^2-5)s cancel out

(n^2-6)/(n^2-2)  

We could further factor this because each is a difference of squares to:

[(n+√6)(n-√6)]/[(n+√2)(n-√2)
8 0
3 years ago
Solve the equation 2^(2x+1)+8=17×2^x.
myrzilka [38]
Oooh, looks fun

ok
erm
we might want to know some properties
(x^m)(x^n)=x^{m+n}
(a^b)^c=a^{bc}
if a^m=a^n where a=a, then assume m=n

2^{2x+1}=(2^{2x})(2^1)
so
(2^{2x})(2)+8=17(2^x)
(2^{2x})(2)+2^3=17(2^x)
(2^x)^2(2)+2^3=17(2^x)
minus 17*2^x both sides
(2^x)^2(2)+2^3-17(2^x)=0
use u subsitution, u=2ˣ
(u)^2(2)+2^3-17(u)=0
solve 2u^2+8-17u=0
or
2u^2-17u+8=0
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
2^3=2^x
3=x

and
\frac{1}{2}=2^x
2^{-1}=2^x
-1=x

x=-1 and 3
neat problem
8 0
3 years ago
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