Answer:
-5,-8,-11,-14,-17
Step-by-step explanation:
-3n -2
n=1 -3(1) -2 = -3-2 = -5
n=2 -3(2) -2 = -6-2 = -8
n=3 -3(3) -2 = -9-2 = -11
n=4 -3(4) -2 = -12-2 = -14
n=5 -3(5) -2 = -15-2 = -17
X/7= 3
⇒ x= 3*7
⇒ x= 21
x/7= 20
⇒ x= 20*7
⇒ x= 140
x/7= 21
⇒ x= 21*7
⇒ x= 147
x/7= 22
⇒ x= 22*7
⇒ x= 154
Hope this helps~
The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
Step-by-step explanation: Using the equation, y = mx + b, the slope-intercept form, plug in the values you have and solve for b. (m is the slope.) You have y = -8 and x = 4 and m = 1/2.
-4/9 = -0.444
<span>-2/7 = -0.29
</span><span>least to greatest</span>
-4/9, -0.434, -0.43, -0.34, -2/7
