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navik [9.2K]
3 years ago
6

Write the standard equation for the circle center (–6, 7), r = 9.

Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Given: The center of the circle is (6,7) and the radius is 9.

To find: The standard equation for the circle.

Solution: The standard equation for the circle with center (a,b) and radius ris given as:

(x-a)^2+(y-b)^2=r^2

Now, the center is (6,7) and the radius is 9, thus the equation of circle is:

(x-(-6))^2+(y-7)^2=(9)^2

(x+6)^2+(y-7)^2=(9)^2

which is the required equation of circle with center as (6,7) and the radius is 9.

Advocard [28]3 years ago
4 0
The standard equation for the circle centre can be written by using this formula: (x-h)² + (y -k)² = r² 

So, the equation in this case is: (x+6)² + (y-7)² = 81
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The arithmetic sequences are as follow:

<h3>What is Arithmetic Sequence?</h3>

An arithmetic sequence in algebra is a sequence of numbers where the difference between every two consecutive terms is the same.

1) t(n) = 5n + 4

t(1) = 9, t(2) = 14, t(3) = 19

So,

9,14,19,...

d= 14-9 = 5

d= 19-14 =5

Hence, it is an AP

2) 1, 2, 4, 8 , 16

Hence, it is not an AP

3) 3, 6, 9 ,...

It is an AP

4)It is given that it is an AP

5) tn =  2*3^n

 t1= 6, t2= 18, t3= 54

So, 6, 18, 54,...

Hence, it is not an AP

6) 3 , 1, 1/3,...

It is not an AP

7) t(n+1)= 6*t(n)

t(1) = -1

t(2)=-6

t(3)= -36

Hence, it is not an AP

8) -3, 1, 5, 9

Hence, it is an AP.

9) 1, 4, 9,...

Hence, it not an AP

10) 2,1,0,1,2,...

It is not an AP

11) t(n)= -2n-5

t(1)= -7, t(2)= -9, t(3)= -11

Hence, it is an AP

12) tn= (1/2)^n

 t1= 1/2, t2= 1/4, t3= 1/8

It is not an AP

Learn more about AP here:

brainly.com/question/24873057

#SPJ1

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