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navik [9.2K]
3 years ago
6

Write the standard equation for the circle center (–6, 7), r = 9.

Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Given: The center of the circle is (6,7) and the radius is 9.

To find: The standard equation for the circle.

Solution: The standard equation for the circle with center (a,b) and radius ris given as:

(x-a)^2+(y-b)^2=r^2

Now, the center is (6,7) and the radius is 9, thus the equation of circle is:

(x-(-6))^2+(y-7)^2=(9)^2

(x+6)^2+(y-7)^2=(9)^2

which is the required equation of circle with center as (6,7) and the radius is 9.

Advocard [28]3 years ago
4 0
The standard equation for the circle centre can be written by using this formula: (x-h)² + (y -k)² = r² 

So, the equation in this case is: (x+6)² + (y-7)² = 81
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A polynomial function of least degree with integral coefficients that has the

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Given

Given zeros are 3i, -1  and 0

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-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

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the factor form of given zeros

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Now we multiply it to get the polynomial

x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x

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Ginny’s favorite cookie recipe requires 1 1/2 cups of sugar to make 24 cookies. How much sugar does Ginny need to make 36 of the
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Ginny needs 2\frac{1}{4} cups of sugar to make 36 cookies.

Step-by-step explanation:

Given,

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Ratio of sugar cups to cookies = \frac{3}{2}:24

Let,

x be the number of cups needed for 36 cookies.

Ratio of sugar cups to cookies = x:36\\

Using proportion;

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Product of mean = Product of extreme

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Dividing both sides by 24

\frac{24x}{24}=\frac{54}{24}\\x=\frac{9}{4}\\x=2\frac{1}{4}

Ginny needs 2\frac{1}{4} cups of sugar to make 36 cookies.

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A sphere with center A is shown. Which represents a tangent?<br> | WE
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Answer:

<h2>The segment FE is a tangent of the sphere.</h2>

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Obseve the sphere in the image attached.

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On the other hand, remember that a tangent is a line that intersects the figure at only one point, otherwise, it would be a secant.

Therefore, segment BC is a secant and segment FE is tangent.

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