X= any coordinate on the x-axis . but I'm confused about the " f "
Answer:
a) 
And replacing we got:

b) 
And then the expected value would be:

Step-by-step explanation:
We assume the following distribution given:
Y 0 1 2 3
P(Y) 0.60 0.25 0.10 0.05
Part a
We can find the expected value with this formula:

And replacing we got:

Part b
If we want to find the expected value of
we need to find the expected value of Y^2 and we have:

And replacing we got:

And then the expected value would be:

Answer:

Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write

------------------------------------------------------------------------------
Explanation:
The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.
So that's how I got

(x is between -4 and 5; inclusive of both endpoints)
Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"
Writing

is the set-builder notation way of expressing the domain. The

portion means "x is a real number"
Answer:
In the coordinate plane we can draw the translation if we know the direction and how far the figure should be moved. To translate the point P(x,y) , a units right and b units up, use P'(x+a,y+b) .
Step-by-step explanation:
We know that the point is in Q II. Thus, the x-coordinate of this point will be negative and the y-coordinate will be positive.
The y-coordinate is essentially given, and is y=4.
Imagine drawing a vertical line thru x=-2. This line will intersect y=4 at (-2,4).
The coordinates of the point are (-2, -4).