Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Yes, 13 is the remainder.
See dat pic for full solution.
Answer:
do 70x70=4,900 than do 100 x100=10,000 than add them to gether and you get 10,4900
Step-by-step explanation:
theres 2 sides not just one
Answer:
b
Step-by-step explanation:
1/5 is equal to 20% =.2 it stops there
Take out common factor, 3 :
3x - 3 = 3(x - 1)
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Answer: 3(x - 1)
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