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navik [9.2K]
3 years ago
6

Write the standard equation for the circle center (–6, 7), r = 9.

Mathematics
2 answers:
HACTEHA [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Given: The center of the circle is (6,7) and the radius is 9.

To find: The standard equation for the circle.

Solution: The standard equation for the circle with center (a,b) and radius ris given as:

(x-a)^2+(y-b)^2=r^2

Now, the center is (6,7) and the radius is 9, thus the equation of circle is:

(x-(-6))^2+(y-7)^2=(9)^2

(x+6)^2+(y-7)^2=(9)^2

which is the required equation of circle with center as (6,7) and the radius is 9.

Advocard [28]3 years ago
4 0
The standard equation for the circle centre can be written by using this formula: (x-h)² + (y -k)² = r² 

So, the equation in this case is: (x+6)² + (y-7)² = 81
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Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17
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The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
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From (1) , (2)  ⇒⇒⇒ ∴ WA = WB  →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW²   → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW²  → (5)
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