I need help solving this problem please

Write the first 5 terms of the recursive sequence defined below. a1=0 an=2(an-1)²-1, for n>1

Aleksandr-060686 [28]

Answer:

0, -1, 1, 1, 1

Step-by-step explanation:

Given recursive formula

a₁ = 0
aₙ = 2(aₙ₋₁)² - 1, for n>1

The first 5 terms are:

a₁ = 0
a₂ = 2(0)² - 1 = 0 - 1 = -1
a₃ = 2(-1)² - 1 = 2 - 1 = 1
a₄ = 2(1)² - 1 = 2 - 1 = 1
a₅ = 2(1)² - 1 = 2 - 1 = 1

7 0

3 years ago

If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

$(C_x,C_y)$ ----> coordinates of point C

we have that

The horizontal distance AB is equal to

$AB_x=10-2=8\ units$

The vertical distance AB is equal to

$AB_y=10-4=6\ units$

Find the horizontal coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

so

$\frac{AC_x}{CB_x}=\frac{3}{1}$

$AC_x=3CB_x$ ----> equation A

$AC_x+CB_x=8$ ----> equation B

substitute equation A in equation B

$3CB_x+CB_x=8$

$4CB_x=8\\CB_x=2$

$AC_x=3(2)=6$

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

$C_x=A_x+AC_x=2+6=8$

Find the vertical coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

so

$\frac{AC_y}{CB_y}=\frac{3}{1}$

$AC_y=3CB_y$ ----> equation A

$AC_y+CB_y=6$ ----> equation B

substitute equation A in equation B

$3CB_y+CB_y=6$

$4CB_y=6\\CB_y=1.5$

$AC_y=3(1.5)=4.5$

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

$C_y=A_y+AC_y=4+4.5=8.5$

therefore

The coordinates of point C are (8,8.5)

5 0

2 years ago

Find the angle measure of PQR

sineoko [7]

Answer:

64 degrees

Step-by-step explanation:

When you have the SRQ angle, you can easily solve for PQR. Luckily, we're given that QRP and PRS are 32 and 84, respectively. Adding this together gives you 116. 116*2 = 232 and 360-232 = 128, and 128/2 = 64.

Please Mark Brainliest if this helps!

8 0

2 years ago

F=G(m1-m2)/d2 solve formula for m1 plz... thank you

antoniya [11.8K]

1. f = g(m1 - m2)/d2

2. f d2 = g(m1 - m2)

3. f d2/g + m1 - m2

4. f d2/g + m2 = m1

5. [Answer] m1 = f d2/g + m2

6 0

2 years ago

A line passes through (−2, 5) and has slope 13 . What is an equation of the line in point-slope form

ruslelena [56]

Y - y1 = m(x - x1)
slope(m) = 13
(-2,5)...x1 = -2 and y1 = 5
sub...pay attention to ur signs
y - 5 = 13(x - (-2)...not done yet
y - 5 = 13(x + 2) <== point slope form

3 0

2 years ago