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3 years ago

The equation X squared plus Y squared minus 2X plus 7Y +1 equals zero can be written as which of the following equations

Mathematics

1 answer:

ad-work [718]3 years ago

6 0

For this case we must write in algebraic symbology the expression described above:

We have an equation, then:

x squared plus y squared: $x ^ 2 + y ^ 2$

minus 2x plus 7y plus 1: $-2x + 7y + 1$

equals zero: $= 0$

We construct the equation:

$x ^ 2 + y ^ 2-2x + 7y + 1 = 0$

Answer:

$x ^ 2 + y ^ 2-2x + 7y + 1 = 0$

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What is the graph of the function f(x) = the quantity of x plus 2, all over x minus 3

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Step-by-step explanation:

The given function is $f(x)=\frac{x+2}{x-3}$ and we need to graph it.

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Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

My name is Ann [436]

Answer:

Part 1) $BE=266\frac{2}{3}\ ft$

Part 2) $PE=233\frac{1}{3}\ ft$

Step-by-step explanation:

Part 1)

Find the distance from B to E

To solve this problem I assume that CGRP is a parallelogram

Triangles CGB and PEB are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

$\frac{BG}{BE}=\frac{CB}{PB}$

substitute the values

$\frac{400}{BE}=\frac{300}{200}$

solve for BE

$BE=400(200)/300$

$BE=\frac{800}{3}\ ft$

Convert to mixed number

$BE=\frac{800}{3}\ ft=\frac{798}{3}+\frac{2}{3}=266\frac{2}{3}\ ft$

Part 2)

Find the distance from P to E

$\frac{CG}{PE}=\frac{CB}{PB}$

substitute the values

$\frac{350}{PE}=\frac{300}{200}$

solve for PE

$PE=350(200)/300$

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