I think its D. $1,800 because 10.4 multiplied by twelve is 124.8 and if you multiply that by 15 you get $1.872.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
42 13/20 km
Step-by-step explanation:
10 3/10+9 7/20+14 7/10+ 8 9/20=41+ (6+7+14+9)/20=41 + 1 13/20= 42 13/20 km
Step-by-step explanation:
4(x-6)=2
4x-24=2
4x=2+24
4x=28
x=7
Answer:
(-2, -3)
Step-by-step explanation:
2x + 1 = 3x + 3
minus 3 from both sides
2x - 2 = 3x
minus 2x from both sides
-2 = x
then plug in -2 for x
y = 2(-2) + 1
y = -4 + 1
y = -3
(-2, -3).
