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sertanlavr [38]
3 years ago
14

What is the equation of the line?

Mathematics
1 answer:
NeTakaya3 years ago
6 0
This line is commonly known as undefined. where the way to find it is x=(x)
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100 POINTS PLEASE HELP ME 100 POINTS (make fullscreen)
Anit [1.1K]

Answer:

  • 1) 64, 2) 6, 3) 26, 4) 33

Step-by-step explanation:

<h3>#1</h3>

<u>Sum of interior angles is 180</u>

  • 70 + 46 + x = 180
  • 116 + x = 180
  • x = 64
<h3>#2</h3>

<u>Sum of interior angles is 180</u>

  • 84 + 7x + 1 + 9x - 1 = 84
  • 16x + 84 = 180
  • 16x = 96
  • x = 6
<h3>#3</h3>

<u>Vertical angles are same, the sum of remaining angles is same for both triangles:</u>

  • 35 + 25 = 34 + x
  • 60 = 34 + x
  • x = 60 - 34
  • x = 26
<h3>#4</h3>

<u>Exterior angle is same as the sum of non-adjacent interior angles:</u>

  • 5x - 7 + 6x + 3 = 84
  • 11x - 4 = 84
  • 11x = 88
  • x = 8
  • m∠G = 5x - 7 = 5*8 - 7 = 40 - 7 = 33
8 0
2 years ago
Read 2 more answers
What is 127 as a percent?
kondor19780726 [428]

Hello!

The answer is 127,000%

3 0
3 years ago
2x10^-4 - 1x10^-5 show work. I got an answer of 1.9x10^-4,
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8 0
3 years ago
Read 2 more answers
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
15, -19, 23, -27.. how would you write that in sigma notation?
sertanlavr [38]

Answer: i think its zero

Step-by-step explanation:

or u can just look it up on an sigma math calculator and that should give u the answer

3 0
2 years ago
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