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Maru [420]
3 years ago
14

Which feature of virtualisation helps increase the IT productivity of a business

Computers and Technology
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer:

Add, remove, organize and reorder commands on the Quick Access Toolbar. ... The Quick Access Toolbar is a customizable toolbar that contains a set of ... The only way to increase the size of the buttons is to lower the screen resolution you use. ... However, you can Customize the ribbon in Office to personalize the ribbon ...

Explanation:

because

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Urgent. I will mark you brainliest. explain why cyber warfare is a real threat.​
stellarik [79]

Answer: Cyber warfare is a real threat since being able to hack another computer especially a countries computer with lots of info in their weaknesses can lead to their downfall. Since they can even possibly if their skilled enough hack their entire data base system and leak it to the public and that wouldn't be good for them not in a single possible way. That's the reason it's dangerous not only that but also because they can access their servers; which can let them access anything online from the whole country including banking information military info which can let them know which area there gonna go to next equipment there gonna bring and where they're gonna launch missiles, bombs, even nukes if they decide to launch one. And being able to hijack the computer that launches the nukes can make the hacker launch the nuke to a different place or launch the nuke on the country trying to launch the nuke.

Explanation:

3 0
2 years ago
Read 2 more answers
Most of us have been using elements of Web 2.0 without even realizing it.<br> True<br> False
aleksandrvk [35]

Answer: True?

Explanation:

I’m pretty sure I’m new to that stuff

5 0
2 years ago
(03.05 LC) Match the term with its description. (4 points) Column A 1. Acid : Acid 2. Alkaline : Alkaline 3. pH : pH 4. Ion : Io
Nady [450]

Answer:

Follows are the matching to this question:

Explanation:

Column  A            Column B

     1                           c

     2                          d

     3                          b

     4                          a

Description of the matching:

  • In 1(Acid) the correct choice is (c) because the acid (HCl) dissociates to both the H+ ion and the Cl- ion as a solution.  
  • In 2(Alkaline ) the correct choice is (d) because alkaline NaOH is a solution that differentiates between the ions ( OH-) and Na+.  
  • In 3(pH ) the correct choice is (b) because for an A compound of less than 7 is an acid and an alkaline pH compound of more than 7. For neutral compounds, a pH of 7 is applicable.
  • In 4(Ion) the correct choice is (a) because Na+ ion is loaded positive, and Cl-ion is loaded negatively.
8 0
2 years ago
Given a string variable string 's;', implement a tokenizer to identify the unique tokens contained in this string, identify all
Flauer [41]

Answer:

#include <iostream>

#include <string>

#include <vector>

#include <cctype>

#include <algorithm>

using namespace std;

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols);

struct TokenFreq{

string token;

int freq;

};

string spaces(string& istr, string& newstr);

void printVector(vector<TokenFreq> & tfVec);

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVecVec);

void selectionSort( vector<TokenFreq> & tokFreqVector );  

void insertionSort( vector<TokenFreq> & tokFreqVector );

//main

int main(int argc, const char * argv[]) {

 

vector<vector<int> > matrix;

matrixInit(matrix, 3, 4);

 

string ostr1 = " I do keep the main points straight in my head most of the time, and I do know where to find the details when I need them. by Bjarne Stroustrup";

string ostr2 = " ";

string ostr3 = "Your time is limited, so don’t waste it living someone else’s life.Stay Hungry. Stay Foolish.";

//string ostr = ostr2;

string istr;

 

cout << "Enter the text: ";

getline(cin, istr);

vector<TokenFreq> tfVec;

getTokenFreqVec(istr, tfVec);

selectionSort(tfVec);

insertionSort(tfVec);

return 0;

}

//-----

void selectionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int min;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

min = i;

for (int j = i+1; j <int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq < tokFreqVector[min].freq)

min = j;

}

if(min!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[min];

tokFreqVector[min] = temp;

}

}

cout<<"-----selectionSort------------------"<<endl;

printVector(tokFreqVector);

}

void insertionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int max;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

max = i;

for (int j = i+1; j < int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq > tokFreqVector[max].freq)

max = j;

}

if(max!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[max];

tokFreqVector[max] = temp;

}

}

cout<<"-----insertionsort------------------"<<endl;

printVector(tokFreqVector);

}

string spaces(string& istr, string & newstr){

int j;

//Check double space and create new string with lowercase

for (int i = 0; i < int(istr.length()); ++i){

istr[i] = tolower(istr[i]);

if (isspace(istr[i])){

//check double space again

j = i+1;

while(true){

if (istr[j] == '\342') istr[j]=' ';

if (istr[j] == '\200') istr[j]=' ';

if (istr[j] == '\224') istr[j]=' ';

if(isspace(istr[j])) j++;

else break;

}

i=j-1;

newstr = newstr + istr[i];

}else

newstr = newstr + istr[i];

}

return newstr;

}

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVec){

string newstr;

int curr_beg = 0;

int curr_end = 0;

string word;

bool check = false;

int index=0;

 

//call func spaces to get new string

newstr = spaces(istr, newstr);

//cout << newstr << endl;

//cout << endl;

//cout << newstr << "||" << endl;

string tempstr = newstr;

 

if(newstr != " "){

tfVec.push_back(TokenFreq());

}

for (int i = 0; i < int(newstr.length()); ++i){

if(isspace(newstr[i])){

check = false;

 

curr_end = i;

word = tempstr.substr(curr_beg, curr_end - curr_beg);

curr_beg = i + 1;

 

for (int j = 0; j < int(tfVec.size()); j++){

if (tfVec[j].token == word){

tfVec[j].freq++;

check = true;

 

break;

}

}//end-for;

if (check == false && i!=(int(newstr.length())-1)){

//cout <<"**"<< word <<"**"<<word.length()<< endl;

tfVec[index].token=word;

tfVec[index].freq=1;

index++;

tfVec.push_back(TokenFreq());

}

word = "";

//add last value

}

}//end-for

 

if(!isspace(newstr[int(newstr.length())-1])){

word = tempstr.substr(curr_beg, curr_end - (int(newstr.length())-1));

tfVec[index].token=word;

tfVec[index].freq=1;

//tfVec.push_back(TokenFreq());

}

 

printVector(tfVec);

}

void printVector(vector<TokenFreq> & tfVec){

 

cout << "size= {" << tfVec.size() << endl;

for (int i = 0; i < int(tfVec.size()); i++){

cout << " [" << i << "] = (token = \""<< tfVec[i].token <<"\", freq = " << tfVec[i].freq << ")" << endl;

//cout << tfVec[i].token<<endl;;

}

cout << endl;

}

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols){

int i;

int j;

matrix.resize(numRows, vector<int>(numCols) );

for(i = 0; i< numRows; i++ ){

for(j = 0; j < numCols; j++ )

matrix[i][j] = i*j;

}

 

cout << "size of matrix is: " << numRows << "x" << numCols << endl;

for (i = 0; i < numRows; i++){

for (j = 0; j < numCols; j++){

cout<< "matrix[" << i << "][" << i << "]=" << matrix[i][j] << endl;

}

}

cout << endl;

}

Explanation:

3 0
2 years ago
A written document containing a description of a property as of the day of inspection is called a(n) 
meriva
D. An inspection report! Hope this helps!
5 0
3 years ago
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