Answer:
Explanation:
Well here you only have to add 2 new horses .... so simply what you can do is find 2 slots where the gap is maximum ... lets take the given example in detail to understand the same.... here 10001001000010 here you can observe that the difference between the first two filled slots is 3 then 2 then 4 then 1....... make it a separate array ...... now as i said that we just need to place two new horses so we just need two of the biggest numbers from this array and place the new horses at the center of the corresponding slots ... like here 3 and 4 are greatest ... so one horse is placed in between the gap corresponding to 3 while other at 4 ..... after making the new array answer can be find in linear time itself... I hope this makes sense ....
Now lets understand how to program it easily so firstly after scanning all stuff ..... we will make a gap array .... then just think now what we will do is find the greatest two numbers then again putting the horses and then find our answers .... so now an easy approach is that instead of making the string again and again searching for answer .... what we do is just do half of the two greatest ones and again find the greatest one in array....
Answer:
import random
numbers = []
even = 0
odd = 0
for i in range(100):
numbers.append(random.randint(1, 200))
for i in range(100):
if numbers[i] % 2 == 0:
even += 1
else:
odd += 1
print("Even:", even)
print("Odd:", odd)
Explanation:
Gg ez.
Answer:
To do this you'll need to use malloc to assign memory to the pointers used. You'll also need to use free to unassign that memory at the end of the program using the free. Both of these are in stdlib.h.
#include <stdlib.h>
#include <stdio.h>
#define SIZE_X 3
#define SIZE_Y 4
int main(void){
int **matrix, i, j;
// allocate the memory
matrix = (int**)malloc(SIZE_X * sizeof(int*));
for(i = 0; i < SIZE_X; i++){
matrix[i] = (int *)malloc(SIZE_Y * sizeof(int));
}
// assign the values
for(i = 0; i < SIZE_X; i++){
for(j = 0; j < SIZE_Y; j++){
matrix[i][j] = SIZE_Y * i + j + 1;
}
}
// print it out
for(i = 0; i < SIZE_X; i++){
for(j = 0; j < SIZE_X; j++){
printf("%d, %d: %d\n", i, j, matrix[i][j]);
}
}
// free the memory
for(i = 0; i < SIZE_X; i++){
free(matrix[i]);
}
free(matrix);
return 0;
}
Answer:
The answer is by using a covert channel like shared memory objects such as files, directories,messages, etc since both the user and the sender of the document are on same network of the company.
Explanation:
The Bell LaPadula MultiLevel Security model was a security policy developed by Bell and LaPadula in 1973 in response to a security issue raised by the US Air Force regarding file-sharing mainframe computers . Actually, many people with networked systems have realized by early 1970s that the protection purportedly offered by many commercial operating systems was poor, and wa not getting better any time soon. This was observed when it was noticed that as one operating system error was fixed, some other vulnerability would be discovered. There was also the constant worry that various unskilled users would discover loopholes in the operating system during usage and use them to their own advantage.
Information release may take place via shared memory objects such as files, directories, messages, and so on. Thus, a Trojan Horse acting on behalf of a user could release user-private information using legitimate operating system requests. Although developers can build various mechanisms within an operating system to restrict the activity of programs (and Trojan Horses) operating on behalf of a user , there is no general way, short of implementing nondiscretionary policy models, to restrict the activity of such programs. Thus, given that discretionary models cannot prevent the release of sensitive information through legitimate program activity, it is not meaningful to consider how these programs might release information illicitly by using covert channels.
For example, for someone with higher integrity level (SECRET) to send an accounts payable application to a user, if the untrusted accounts payable application contains a Trojan Horse, the Trojan Horse program could send a (legal) message to the said user process running at a lower integrity level (CONFIDENTIAL), thereby initiating the use of a covert channel. In this covert channel, the Trojan Horse is the receiver of (illegal) lower integrity-level input and the user process is the sender of this input.
Answer:
The rising of shied hero, last hope, and dragon pilot.
