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Bas_tet [7]
3 years ago
15

The Coins class was created to hold all your loose change, kind of like a piggy bank! For this exercise, you are going to simula

te starting a bank with a specific number of coins, then adding to your piggy bank to bring your total to $2.12. What you need to do: Create a Coins object that initially has 4 quarters, 3 dimes, 2 nickels, and 1 penny. After you create the initial object, print out the total, then add coins to your bank until you have a total of 15 coins totaling 2.12. You will need to figure out which combination gets you to the correct total with the correct number of coins! When you are finished, call the method to print the bank count then the bank total to verify that you got the correct values.
Computers and Technology
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

Coins c1 = new Coins (4, 3, 2, 1);

     c1.bankValue();

     c1.addQuarter();

     c1.addQuarter();

     c1.addDime();

     c1.addDime();

     c1.addPenny();

     c1.bankCount();

     c1.bankValue();

Explanation:

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Answer:

a. labels

Explanation:

a. labels b. graphs c. numbers d. formulas

It is the labels, which is the title of each column. For one column we can have the names, for another column, we can have a label grade. and for the third column, we can have the label scores. And the others are the graphs, formulas and the numbers, which are not an option.

6 0
3 years ago
File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

       amount = input.nextInt();

       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

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Answer:

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